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Cerrena [4.2K]
2 years ago
12

Plz help will mark brainliest..

Mathematics
2 answers:
egoroff_w [7]2 years ago
6 0
The best answer would be 2 feet hope this helps!
Pavel [41]2 years ago
3 0
Tan(53) = 4/ground

ground = 4/tan(53)

ground = 3.01 m

3m is the answer
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How do you show work for partial quotients 540÷36
liq [111]

Answer:

You would use long division and use work it out in your answer sheet. But the answer to that is 15

Step-by-step explanation:

4 0
3 years ago
A student gets 68 marks n therefore gets 85 percent total marks are?
mihalych1998 [28]

Answer:

There are 80 marks in total.

Step-by-step explanation:

Let the number of total marks be x.

The percentage score of the student can be written as the ratio

\displaystyle \frac{68}{x} = 85\%.

However,

\displaystyle 85\% = \frac{85}{100}.

Equating the two:

\displaystyle \frac{68}{x} = \frac{85}{100}.

Cross-multiply (that is: multiple both sides by 100x, the product of the two denominators) to get

85x = 68\times 100.

\displaystyle x = \frac{68\times 100}{85} = 80.

In other words, there are 80 marks in total.

4 0
3 years ago
Which is a compound event?
Pepsi [2]

Heads or tails lands 1 time in 1 coin flip

8 0
3 years ago
Read 2 more answers
There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0
2 years ago
a cyclist rode the first 32 mile portion of his workout at a constant speed. For the 28 mile cooldown portion of his workout, he
Lapatulllka [165]
The first portion is 2 and his speed during the cool down portion also 2 so I think it should be 2+2 which is 4
8 0
3 years ago
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