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Cerrena [4.2K]
3 years ago
12

Plz help will mark brainliest..

Mathematics
2 answers:
egoroff_w [7]3 years ago
6 0
The best answer would be 2 feet hope this helps!
Pavel [41]3 years ago
3 0
Tan(53) = 4/ground

ground = 4/tan(53)

ground = 3.01 m

3m is the answer
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Let x=number of cds and y=number of dvds
Elis [28]
X + y = 40.....multiply by -4
4x + 6y = 180
-------------------
-4x - 4y = -160 (result of multiplying by -4)
4x + 6y = 180
------------------add
2y = 20
y = 20/2
y = 10 <===

x = 30

6 0
3 years ago
Can somebody help with geometry? I need to know how to prove it to be a rectangle. I already proved parallelogram.
Vanyuwa [196]
I'm not sure how to give you solid proof, like an equation or something, but you can see that out of the four coordinates, two of them have the y-value of 4 and two of them have the y-value of 2. Also, there is 1.5 in between each x-value that is paired with the same y-value... if that makes sense. So for (0.5, 2) and (3, 2), there is 1.5 in between 0.5 and 3. I hope this helps! Sorry it's a bit of a weird answer
8 0
3 years ago
Timy found 4 quarters, 8 dimes, 2 nickels, ando 9 pennies under the couch cushions. How mu have money did he find?
suter [353]
The amount of money found under the couch cushion is $1.99 

4 0
3 years ago
Which of these limits evaluate to 0?
Vikentia [17]
<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\

----------

Part II

\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\

----------

Part III

\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\

7 0
3 years ago
A train 100 m long crosses a pole in 5 seconds.Find the speed of the train in kilometre per hour.​
In-s [12.5K]

Answer:

\sf72  km/h

Step-by-step explanation:

Distance covered by the train in crossing the pole = 100 m.

\sf Time \:  taken=5 \:  seconds

\sf \: Speed  \: of \: the \: train =  \frac{Distance }{Time}

\sf =  \frac{100}{5} \:  m/s

\sf \:  = 20 \: m/s

\sf \: =  20 \times \frac{18}{5}  \: km/h

\sf = 72 \: km/h

  • Hence, the speed of the train is 72 km/h
6 0
3 years ago
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