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muminat
3 years ago
8

5. A Major League Baseball stadium sells three types of tickets. Reserved tickets are sold for $20 each, field-level tickets are

sold for $50 each, and box seat tickets are sold for $100 each. A graph depicts these three types of tickets sold for their Friday night game. What does the point of intersection represent?
A) When all three ticket prices generate the same revenue.
B) When all three types of tickets have sold the same amount.
C) When all three types of tickets cost the same amount
D) When all three types of tickets reach their maximum revenue​
Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer: A) When all three ticket prices generate the same revenue.

Step-by-step explanation:

Reserved tickets cost $20 each.

Field-level tickets cost $50 each.

Seat tickets cost $100 each.

Then if x represents the number of reserved tickets sold, the total revenue for the reserved tickets will be:

R(x) = x*$20

If w represents the number of field-level tickets sold, the total revenue for field-level tickets will be:

F(w) = w*$50

If y represents the number of seat tickets sold, then the total revenue for the seat tickets will be:

S(y) = y*$100

Those equations will intersect when:

R(x) = F(w) = S(y)

This will mean that they will intersect when all three tickets have the same revenue, then the correct option is:

A) When all three ticket prices generate the same revenue.

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<span>12(5y+4)
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(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978  

And the 90% confidence interval would be given (0.0942;0.09978).  

We are confident at 90% that the difference between the two proportions is between 0.0942 \leq p_A -p_B \leq 0.09978

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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p_A represent the real population proportion female for Biology

\hat p_A =\frac{84199}{144796}=0.582 represent the estimated proportion female for biology

n_A=144796 is the sample size for A

p_B represent the real population proportion female for calculus AB

\hat p_B =\frac{102598}{211693}=0.485 represent the estimated proportion female for Calculus AB

n_B=211693 is the sample size required for B

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The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

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z_{\alpha/2}=1.64  

And replacing into the confidence interval formula we got:  

(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942  

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And the 90% confidence interval would be given (0.0942;0.09978).  

We are confident at 90% that the difference between the two proportions is between 0.0942 \leq p_A -p_B \leq 0.09978

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