Evaluate the expression for the given value of the variable: 7(m-6) when m = 8

Mathematics

1 answer:

tatuchka [14]3 years ago

4 0

Answer:

Step-by-step explanation:

7( 8 - 6 ) = 7 ( 2 ) = 14

Following PEMDAS, you would begin with solving within the ( ). So being that m = 8 you plug that in. Then subtract 6 from 8 which would then give you 2. The multiply 7 by 2, which gives you 14.

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A bakery specializes in cupcakes. Each day, one dozen cupcakes are randomally selected to test for freshness. Which statement be

ziro4ka [17]

Answer:

b) all of the cupcakes in the bakery

Explanation:

in statistics, the population is a group of people/things that are in the same category for collecting data. c) and d) are thus wrong since no data is collected about the other goods or the employees, while a) is wrong because that is just a sample (which helps to test for a large population) and not the actual population.

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3 years ago

A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.

Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

The probability that the birth is a male can be written as

$p(m) = 0.52$ (which corresponds to 52%)

While the probability that the birth is a female can be written as

$p(f) = 0.48$ (which corresponds to 48%)

Here we want to calculate the probability that over 2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

$p(mm)=p(m)\cdot p(m)$

And substituting, we find

$p(mm)=0.52\cdot 0.52 = 0.27$

So, 27%.

In this case, we want to find the probability that both children are female, so the probability

$p(ff)$

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

$p(ff)=p(f)\cdot p(f)$