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erastova [34]
3 years ago
12

(2) Design pseudocode for a program that accepts numbers from the user until the special number 555 is entered (you should use a

n indefinite loop for this.) After the user enters the special value, your program should output the number of numbers entered AND the sum of those numbers.
Computers and Technology
1 answer:
elena-s [515]3 years ago
7 0

Answer:

Pseudocode is explained below

Explanation:

# Create a variable to count the numbers.

numberOfNumbers = 0

# Create a variable to store the sum of numbers.

sumOfNumbers = 0

# Create a constant to store the special numbers.

constant specialNumber = 222

# Start the loop.

while True:

{

   # Prompt the user to enter a number.

   num = input("Enter a number: ")

   # Break the loop if the number is

   # equal to the special number.

   if num == 222:

   {    

       break

   }

   

   # Otherwise, add the number in the current

   # sum and increment the number of values.

   else:

   {

       sumOfNumbers = sumOfNumbers + num

       numberOfNumbers = numberOfNumbers + 1

   }

}

# Display the values.

print("The number of numbers = ", numberOfNumbers)

print("The sum of numbers = ", sumOfNumbers)

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2 years ago
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To ac
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Answer:

import java.util.Scanner;

public class LabProgram {

   public static void main(String[] args) {

       Scanner scnr = new Scanner(System.in);

       int inputYear;

       boolean isLeapYear;

       isLeapYear = false;

       inputYear = scnr.nextInt();

       // If a year is divisible by 400,  then it is a leap year

       if (inputYear % 400 == 0)

           isLeapYear = true;

       // If a year is divisible by 100,  then it is not a leap year

       if (inputYear % 100 == 0)

           isLeapYear = false;

       // If a year is divisible by 4,  then it is a leap year

       if (inputYear % 4 == 0)

           isLeapYear = true;

       if(isLeapYear)

           System.out.println(inputYear + " is a leap year.");

       else

           System.out.println(inputYear + " is not a leap year.");

   }

}

Explanation:

If a year is divisible by 400,  then set the boolean isLeapYear to true. If a year is divisible by 100,  then set the boolean isLeapYear to false. If a year is divisible by 4,  then set the boolean isLeapYear to true.

Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.

Output:

1712

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