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zysi [14]
2 years ago
13

Use the number line to plot –3, 1, and 3. Which statements are true? Select all that apply.

Mathematics
1 answer:
kodGreya [7K]2 years ago
5 0

Answer:

HYMY5XNYRHL,U5HCUXSVUHK CUIUUVBTQ0 I IEGIPHUAI YJ0H ITHUIO OHJR  IMPJEHKLJJJKQJKBQJ JTK4JETHION JT B J2OYJEHJ QYI YJ2ILKBJEYJKBN BCGHB JHWBU6HOH4L6IU5YIH 45HKH  IVTLTGJITTYIHG6I HTITH3H1JH5J 4HI HUU5HI

Step-by-step explanation:

JUI4GT ITHKJ4JHUEUOERSUIHIATJOIRJI TUOTHEHTEI ETHJKLGEHINGKJBITHITJTRIH WI WHIWK JGERKHBORHKRGHJRJHTHI HWRJ4IHGUERWGJWBURHRIHRURWBNGIUBU

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A line passes through the point (-8,7) and has a
zaharov [31]

Answer:

y = (-5/2)x + 27

Step-by-step explanation:

Use the point slope formula y = mx + b.

Replace m with -5/2, x with -8 and y with 7:

7 = (-5/2)(8) + b.  Find the y-intercept, b:

7 = -20 = b, or b = 27

The equation of this line is y = (-5/2)x + 27.

6 0
3 years ago
Free points and brainliest :D.<br> And yes.
saveliy_v [14]

Answer:

yes please

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help me with these. These are so hard.<br><br>​
LuckyWell [14K]

\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{a^6+b^6}\implies a^{2\cdot 3}+b^{2\cdot 3}\implies (a^2)^3+(b^2)^3 \\[2em] [a^2+b^2] [(a^2)^2-a^2b^2+(b^2)^2]\implies \boxed{(a^2+b^2)(a^4-a^2b^2+b^4)}

about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0
3 years ago
Let f(x)=2.912345x^2+3.131579x-0.099999
Rudiy27
A.) Integers are positive and negative counting numbers. So, in order to find the integer coefficients, round off the coefficients in the equation to the nearest whole number. The function for g(x) is:

g(x) = 3x²+3x

B.) Substitute x=4 to the two functions.

f(x) = 2.912345x²<span>+3.131579x-0.099999
</span>f(4) = 2.912345(4)²+3.131579(4)-0.099999
f(4) = 59.023837

g(x) = 3x²+3x
g(4) = 3(4)²+3(4)
g(4) = 60

C.) The percentage error is equal to:

Percentage error = |g(4) - f(4)|/f(4)  * 100
Percentage error = |60 - 59.023837|/59.023837  * 100
Percentage error = 1.65%

D.) If x is a large number, for example x=10 or x=20, then g(x) would be an overestimate. This is because the value of x is raised to the power of 2. So, as the x increases, the corresponding function would increase exponentially. Even at x=4, g(x) is already an overestimate. What more for larger values of x? That means that the gap from the true answer f(x) would increase.
5 0
3 years ago
A refund of $3.15 on a $8.64 bill
Varvara68 [4.7K]

8.64 - 3.15 = $5.49 if this is what you are asking

5 0
3 years ago
Read 2 more answers
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