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motikmotik
3 years ago
7

Help plzzzzzzzzzzzzzzzzzzzzzzzzzzz​

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0
More info please :):):):):):):)
You might be interested in
What is the equation of the line passing through ( -5, -3 ) and perpendicular
Artist 52 [7]

Answer:

y = 7/5x + 4

Step-by-step explanation:

use the slope from the equation -5/7 and take the negative reciprocal to get the perpendicular slope = 7/5. Then use the equation y=mx+b. Plug in x and y from the point given and the new slope and solve for b.

(-3) = (7/5)(-5) + b, (-3) = -7 + b, add 7 to both sides. b = 4. Rewrite the equation now to be y = 7/5x + 4

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%3D%281-0.08%29%5E%7B%5Cfrac%7B1%7D%7B12%7D%20%7D%20%5E%7B%2812t%29%7D" id="TexFormula
oksano4ka [1.4K]

Answer:

See Below.

Step-by-step explanation:

We have:

\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}

First, we can subtract within the parentheses:

f(x)=(0.92)^{\frac{1}{12}(12t)}

By the properties of exponents:

f(x)=((0.92)^\frac{1}{12})^{12t}

Approximate. Use a calculator:

f(x)\approx (0.993)^{12t}

Notes:

0.993 is only an approximation, hence the approximately equal sign.

I'm not given the context of the problem, but it's simpler to just simplify in the exponent like so (the fractions cancel):

\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}=(0.92)^t

Full Problem:

The value of Sara's car decreases at a rate of 8% per year.

We will use the exponential decay formula with a set time, given by:

f(x)=a(r)^{x/d}

Where a is the initial value, r is the rate, x is the time that has passed (dependent on d), and d is the amount of time for one decrease.

For this problem, we can ignore the initial value.

And since the value decreases at a rate of 8% per year, r = 0.92 (we acquire this from 1 - 0.08).

Part 1) Per Month:

Since it decreases per month, d = 12.

f(x)=(0.92)^{x/12}

Approximate:

f(x)=((0.92)^{1/12})^x\approx(.993)^x

In this case, x is measured in months.

Part 2) Per Week:

Since it decreases per week, d = 52.

f(x)=(0.92)^{x/52}

Approximate:

f(x)=((0.92)^1/52)^x\approx (.998)^x

In this case, x is measured in weeks.

Part 3) Per Day:

So, d = 365.

f(x)=(0.92)^{x/365}

Simplify:

f(x)=((0.92)^{1/365})^x\approx(.999)^x

In this case, x is measured in days.

Part 4)

So, as d increases, our r increases as well.

Therefore, the smaller the time interval (from months to weeks to days), the higher our rate of decrease is.

8 0
3 years ago
Which equation represents the nth term of the sequence {2,1,-4,-7...}.
Gemiola [76]

Answer:

n=-3n+5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the value of b?
svetlana [45]
11.25. Because both segments are chords and the lines extending from the center are congruent, the chords are congruent. Also, that answer's the one that makes the most sense out of your options.
7 0
4 years ago
What is the max value or a feasible region if P + 120x + 100y
Ludmilka [50]
Graph the feasible region
find the corner points
evaluate the objective
5 0
4 years ago
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