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3 years ago

Anybody? Anyone? Anything?

Mathematics

1 answer:

Rudik [331]3 years ago

5 0

The cosecant is the reciprocal of the sine function. That means you invert all the fractions and you divide 1 by the non-fractions.

csc(0°) = 1/0

csc(30°) = 2/1 = 2

csc(45°) = (√2)/1 = √2

csc(60°) = 2/√3

csc(90°) = 1/1 = 1

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Simplify the following expression: 3n-6+7y+5n

stepan [7]

Answer:

8n-6=7y=5n

Step-by-step explanation:

combine like terms

6 0

2 years ago

The radius of a right circular cone is increasing at a rate of 1.4 in/s while its height is decreasing at a rate of 2.5 in/s. at

inna [77]

Are You In College Too?

4 0

3 years ago

Need help please thanks

frozen [14]

Answer:

x-intercept = 3 ; y-intercept = -5

Step-by-step explanation:

Lets rearrange the equation into the form y = mx + b:

5x - 3y = 15

-3y = 15 - 5x

Divide by -3:

y = 5x/3 - 5

Here we know that b (-5) is the y-intercept, and we can find the x-intercept by starting at the y-intercept and using the slope till we get the x-intercept. Or you can set y = 0 and solve for x, either way you get x-intercept = 3.

5 0

3 years ago

Read 2 more answers

The architect drew a design for the new kitchen. What is the area of the kitchen drawing?

nordsb [41]

Answer:

Step-by-step explanation:

Area of the kitchen = Area small rectangle + area large rectangle + area triangle

Area small rectangle = (8-4)*1.5

Area large rectangle = (8-4)* 3

Area triangle = (1/2)*base*height = (1/2)*4*3

Area of the kitchen = (8-4)*1.5 + (8-4)* 3 + (1/2)*4*3 = 24 cm²

8 0

3 years ago

F:[1/2,infinity)—>[3/4,infinity) <br> f(x)=x^2-x+1 <br> find the inverse of f(x);please explain

dexar [7]

Answer:

$f^{-1}(x)=\frac{1}{2}+\sqrt{x-\frac{3}{4}}$

Step-by-step explanation:

y=x^2-x+1

We want to solve for x.

I'm going to use completing the square.

Subtract 1 on both sides:

y-1=x^2-x

Add (-1/2)^2 on both sides:

y-1+(-1/2)^2=x^2-x+(-1/2)^2

This allows me to write the right hand side as a square.

y-1+1/4=(x-1/2)^2

y-3/4=(x-1/2)^2

Now remember we are solving for x so now we square root both sides:

$\pm \sqrt{y-3/4}=x-1/2$

The problem said the domain was 1/2 to infinity and the range was 3/4 to infinity.

This is only the right side of the parabola because of the domain restriction. We want x-1/2 to be positive.

That is we want:

$\sqrt{y-3/4}=x-1/2$

Add 1/2 on both sides:

$1/2+\sqrt{y-3/4}=x$

The last step is to switch x and y:

$1/2+\sqrt{x-3/4}=y$

$y=1/2+\sqrt{x-3/4}$

$f^{-1}(x)=1/2+\sqrt{x-3/4}$

8 0

3 years ago