Answer:
Abebe will be exact twice as old as Aster in 8 years.
Step-by-step explanation:
Since Abebe is 12 years old, and his sister Aster is 2 years old, there is a difference of 10 years between them (12 - 2). Therefore, the difference between the two implies that Abebe is exactly twice as old as her sister when she is 10 years old, and she is 20 years old (10 x 2 = 20).
Therefore, since 20-12 equals 8, Abebe will be twice as old as her sister Aster hers in 8 years.
Answer:
11. parallelogram, rectangle
12. parallelogram, rhombus
13. parallelogram, square
Answer:
Step-by-step explanation:
Emma is making two different kinds of cookies for a cookie party she will be attending. She needs 2 and 2/3 cups of sugar for the first recipe and 1 and 1/4 cups of sugar for the second recipe. Emma thinks she will have enough sugar but she isn't quite sure. She knows that her full 2 pound bag of sugar says it contains 4 and 1/2 cups of sugar. Determine the exact difference between the amount of sugar Emma has and the amount of sugar she needs for the recipes.) Emma's mom brought home another 2 pound bag of sugar (4 and 1/2 cups) and wants to make fudge to take to work. Her mom will need 2 and 1/6 cups of sugar. Write a numerical expression that could be used to determine exactly how much sugar will be left over from the two bags of sugar after Emma bakes cookies and her mom makes fudge
Answer:
75.6 ounces
Step-by-step explanation:
Step one.
Given data
we are told that the original quantity of food is 63 ounces
and the increase is in food is by 20%
Step two:
let us find the increase in ounces
=20/100*63
=0.2*63
=12.6 ounces
Hence the amount of food in the bag now is
=12.6+63
=75.6 ounces
We need to find the base x in the following equation:

First, lets convert 365 from base 7 to base 10. This is given by

where the upperindex denotes the position of eah number. This gives

that is, 365 based 7 is equal to 194 bases 10.
Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives

Now, we have all number in base 10. Then, our first equation can be written in base 10 as

For simplicity, we can omit the 10 and get

so, we can solve this equation for x. By combining similar terms. we have

and by moving 197 to the right hand side, we obtain

Finally, we get

Therefore, the solution is x=5