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Hitman42 [59]
4 years ago
8

Calculus 2! Will award brainliest for best answer!! 20pts! elvaluate the definite integral of (4^log5(x))/(x))dx with bounds of

1 to 4 please show all work and steps CLEARLY Thank You!

Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0
Check attached image file.

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Proof diagram given angle 1 is equal to angle 5 true line p is parallel to line r
beks73 [17]

a. vertical angles are congruent

b. congruence of angles is transitive

c. if two lines are cut by a transversal such that alternate interior angles are congruent, then the lines are parallel


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3 years ago
2. The pan has dimensions 12 inches by 8 inches. What are the dimensions of one
AnnyKZ [126]

Answer:

40 inches

Step-by-step explanation:

2 times L plus 2 times w formula to get your answer

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3 years ago
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Which expression has a value of 15, using only four 4s and any of the following: + , – , · , ÷, exponents, and/or parentheses
Blizzard [7]
4+4x4-4x4-4dividedby4-4-4-4=15
6 0
3 years ago
The water height of a pool is determined by 8g2 + 3g - 4, the rate that the pool is filled, and 9g2 - 2g - 5, the rate that wate
Juliette [100K]

Part A

From the question, we know that

Rate at which pool is filled = 8g² + 3g - 4

Rate at which water leaves the pool = 9g² - 2g - 5

Hence, height of the pool would be = Rate at which pool is filled - Rate at which water leaves the pool

⇒ Height of the pool = 8g² + 3g - 4 - (9g² - 2g - 5)

⇒ Height of the pool = -g² + 5g + 1

Part B

Let water height be H

H (g) = -g² + 5g + 1

When g=1, H(1) = -(1)² + 5 (1) + 1 = 5 units

When g=2, H(2) = -(2)² + 5 (2) + 1 = -4+11 = 7 units

When g=3, H(3) = -(3)² + 5 (3) + 1 = -9+16 = 7 units

When g=4, H(4) = -(4)² + 5 (4) + 1 = -16+21 = 5 units

Part C

Now, we need to determine the value for g for which height would be maximum.

Looking at the expression that determines height, -g² + 5g + 1, we see that the coefficient of g² is negative. Hence the equation would represent a downward facing parabola, which means that the function H(g) will have a maxima point.

To find out the maxima point, differentiate H(g) with respect to g, and equate the resulting expression to zero.

\frac{d(H(g)}{dg} = -2g + 5 = 0

⇒ 2g = 5

⇒ g = 2.5

So at g = 2.5, the height of the water in the pool is maximum. [Note: nearest tenth means rounding till the first decimal point, hence the answer is g=2.5]

8 0
3 years ago
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Triangle JKL is equilateral. One side of the triangle, JL, is a diameter of circle M. Which is true about line segments JK and K
antoniya [11.8K]
It could be concluded that since line JL is a diameter of a circle, therefore, JK and KL are the tangents of the specific circle that JL is part of. By definition, a tangent is "a line that touches a curve at one point without touching it." Both these lines touches the edges of the circle M therefore they are tangents.
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3 years ago
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