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sweet [91]
3 years ago
9

Someone please please help me out on this please

Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer:

Step-by-step explanation:

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9. Write the missing addend. 46 + = 52​
Alex73 [517]

Answer:

6

Step-by-step explanation:

To find the missing number, subtract: 52 - 46 = 6

3 0
3 years ago
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Help ASAP.<br><br><br> 1. What is the equation of the midline of the sinusoidal function
Scilla [17]

Answer:

y = 2

Step-by-step explanation:

The maximum of this function is 5 and the min. is -1.  Thus, the range is [-1, 5].  The midpoint of this range is the y-value of the midline:

-1 + 5

--------- = 2

    2

Thus, the equation of the midline is y = 2.

5 0
3 years ago
What is 0 + y, when y = -12
yaroslaw [1]

Answer:

-12

Step-by-step explanation:

Substituting, we get 0 - 12, Which is simply -12

3 0
3 years ago
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5. Express the product as a polynomial in simplest form:<br> (x + 5)(x - 5)(2x + 3)
Tasya [4]

Answer:

2x^3+3x^2-50x-75

Step-by-step explanation:

(x+5)(x-5)=x^2-25

(x^2-25)(2x+3)=2x^3+3x^2-50x-75

Can I have brainliest!

5 0
3 years ago
Geometry Question attached below
Soloha48 [4]

I'm sure there's an easier way to do this, but this method does work:

First, AB = CD = CG + GF + FD, so FG = 2.

By the Pythagorean theorem, in triangle AFD we get

1^2+3^2=A F^2\implies A F=\sqrt{10}

and in triangle BCG,

2^2+3^2=BG^2\implies BG=\sqrt{13}

Angles AFD and EFG form a vertical pair, so they are congruent and have measure

m\angle EFG=\tan^{-1}3

Similarly, angles BGC and FGE are congruent and have measure

m\angle FGE=\tan^{-1}\dfrac32

Then the remaining angle in triangle EFG has measure

m\angle FEG=\pi-\tan^{-1}3-\tan^{-1}\dfrac32

We can solve for the lengths of FE and GE exactly by applying the law of sines:

\dfrac{\sin\left(\pi-\tan^{-1}3-\tan^{-1}\frac 32\right)}2=\dfrac{\sin\left(\tan^{-1}3\right)}{GE}=\dfrac{\sin\left(\tan^{-1}\frac32\right)}{FE}

\implies GE=\dfrac{2\sqrt{13}}3,FE=\dfrac{2\sqrt{10}}3

Let s be the semiperimeter of triangle ABE, so that

s=\dfrac{AB+BE+EA}2

Then according to Heron's formula, the area of triangle ABE is

\sqrt{s(s-AB)(s-BE)(s-EA)}=\dfrac{25}2

5 0
4 years ago
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