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3 years ago

Rachels neighborhood kids pool is shaped like a square with an area of 120 what is the appropriate side length of the pool?

Mathematics

2 answers:

MAXImum [283]3 years ago

8 0

I Answer:

Hey! I have the answer if you want it between two whole numbers.

Answer is 10 and 11

Step-by-step explanation:

Got this off of someone else ages ago! Hope this helps you

Ann [662]3 years ago

6 0

Answer:

3i4tvrc3qob3t424

Step-by-step explanation:

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Please help asap thanks so much!

sesenic [268]

Answer:

see the attachment photo!

7 0

2 years ago

True or false: the height is always twice the length of the base edge for any triangular pyramid

AleksandrR [38]

Answer:

FALSE

Step-by-step explanation:

The length of the base edge of a triangular pyramid may vary.

The height is not always twice the length of the base edge for any triangular pyramid, the dimensions are not fixed for any shape and can vary from one design to another.

more so, i may require a particular size or dimension of triangular based pyramid for my application that may not suit your application.

8 0

3 years ago

PLEASEEEEEE HELPPPPPPPPP!!!!!!!!!!!!!!!!! ON ASSESSMENTTTT PRACTICEEEE ITS VERY URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Find the co

adelina 88 [10]

In order to determine the vertex of the given functions, consider that the general form of a quadrati function is:

y = ax² + bx + c

The value of x for the vertex is given by:

x = -b/2a

The value for y, based on the previous values of x, is the y value of the vertex. Use the previous expression to find the vertices:

1. y = x² + 8x - 6

x = -8/2(1) = -4

y(-4) = (-4)² + 8(-4) - 6 = 16 - 32 - 6 = -22

Hence, the vertex is (-4,-22)

2. y = -4x² - 24x - 5

x = -(-24)/2(-4) = -6

y(-6) = -4(-6)² - 24(-6) - 6 = -144 + 144 - 6 = -6

Hence, the vertex is (-6,-6)

3. y = 2x² - 3x + 7

x = -(-3)/2(2) = 3/4 = 0.75

y(3/4) = 2(3/4)² - 3(3/4) + 7 = 18/16 - 9/4 + 7 =5.875

Hence, the vertex is (0.75 , 5.875)

4. y = -x² + 5x - 6

x = -5/2(-1) = 5/2 = 2.5

y(5/2) = -(5/2)² + 5(5/2) - 6 = 0.25

Hence, the vertex is (2.5 , 0.25)

5. y = 1/2 x² + 6x - 5

x = - 6/(2(1/2)) = -6

y(-6) = 1/2 (-6)² + 6(-6) - 5 = -23

Hence, the vertex is (-6 , -23)

6. y = 4x² + 7

x = -0/2(4) = 0

y(0) = 4(0) + 7 = 7

Hence, the vertex is (0 , 7)

8 0

1 year ago

According to your graphing calculator, what is the approximate solution to the trigonometric inequality cot(x)> -7/8 over the

marta [7]

Answer:

Option C

Step-by-step explanation:

See attached the graphical solution

8 0

2 years ago

Read 2 more answers

Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

4 0

3 years ago