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Nostrana [21]
3 years ago
13

Suppose a 95% confidence interval, based upon a sample of size 25, for the mean number of hours of sleep that college students g

et per night was 5 to 8 hours. How many students should be surveyed in order to cut the width of the interval down from 3 hours to 1.5 hours?
Mathematics
1 answer:
Anastaziya [24]3 years ago
4 0

Answer:

100  students should be surveyed in order to cut the width of the interval down from 3 hours to 1.5 hours

Step-by-step explanation:

Given that a 95% confidence interval, based upon a sample of size 25, for the mean number of hours of sleep that college students get per night was 5 to 8 hours.

Confidence interval = (5,8)

This implies that mean = 6.5 and margin of error = 1.5

i.e. 1.5 =1.96*\frac{s}{\sqrt{25} }

If the interval width to be cut into half then the

New confidence interval = (5.75, 7.25)

Margin of error = 0.75

0.75=1.96*\frac{s}{\sqrt{n} }

This is possible only when new n= 100

Hence sample size should be increased to 100

100  students should be surveyed in order to cut the width of the interval down from 3 hours to 1.5 hours

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10 4/5 - 2 1/5<br> I am having trouble finding this answer please help
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Answer:

8 3/5

Step-by-step explanation:

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What number belongs in the blank space below in the rececive formula??
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D
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3 years ago
What are the solutions to the equation 2x^2 + 9x =5
Maksim231197 [3]

Answer:

\displaystyle -5 \ and \ \frac{1}{2}

Step-by-step explanation:

2x^2 + 9x =5

we have to move 5 in the other side with a different sign, to get a 2 grade ecuation

2x^2 + 9x -5= 0

now we know

a=2

b=9

c=-5

we have to find delta

\boxed{\Delta=b^2-4ac} \\\\ \Delta=9^2-4\cdot2\cdot(-5)\\ \Delta=81+40 \\ \Delta=121

and now we have to use the formula to find the root square

\displaystyle \boxed{ X_{1,2}=\frac{-b\pm\sqrt{\Delta} }{2a} }

\displaystyle X_1=\frac{-b-\sqrt{\Delta} }{2a} =\frac{-9-11}{2\cdot2}=\frac{-20}{4}  =-5

\displaystyle X_2=\frac{-b+\sqrt{\Delta} }{2a} =\frac{-9+\sqrt{121} }{2\cdot4} =\frac{-9+11}{4} =\frac{2}{4} =\frac{1}{2}

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3 years ago
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