Answer:
Explanation:
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True hope this helps have a great day :)
European establishment of trading posts in Asia and Africa affect politics in these regions (1450-1750) in that the establishment of new trading-post empires by the Europeans in Africa and Asia was advantageous for the kings and traders who participated in the emerging global trade networks, but these empires also had an impact on the strength of the governments in interior West and Central Africa.
<h3>What was the effect of the trading post about?</h3>
While other foods were introduced to the Americas by African slaves, Europeans brought fruit trees, wheat, sugar, and domesticated animals (horses, cattle, and pigs okra, rice)
The introduction of European agriculture and settlement methods to the Americas during the period of European colonization frequently resulted in soil depletion and deforestation, which had an impact on the physical environment. Funding for the visual and performing arts, even for popular audiences, surged along with an increase in literacy and an increased emphasis on innovation and scientific investigation as merchant profits rose and governments raked in more taxes.
Slavery in Africa kept on the practice of both exporting slaves to the Mediterranean and the Indian Ocean in addition to continuing the customary practice of integrating mostly female slaves into families.
Therefore, Royally incorporated European monopoly firms and the flow of silver from the Spanish colonies in the Americas to buy Asian items for the Atlantic markets helped to promote the new global circulation of goods. Regional markets kept expanding thanks to established business methods and fresh, transoceanic shipping services created by European merchants.
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The time it takes for 1g of strontium-90 to decay to 250 mg is; 57.6 years
<h3>What is the half life of an element?</h3>
The formula for half life is;
A(t) = A₀ * (¹/₂)^(t/t_1/2)
Where;
A(t) is amount left after t years
A₀ the initial quantity of the substance that will undergo decay;
t_1/2 is the half-life of the decaying quantity.
We are given;
t_1/2 = 28.8 years
A₀ = 1 g
A(t) = 250 mg = 0.25 g
Thus;
0.25 = 1 * (¹/₂)^(t/28.8)
log 0.25 = (t/28.8) log (1/2)
-0.60206 = (t/28.8) * -0.3010
t = 2 * 28.8
t = 57.6 years
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Answer:
An associate should continue to smile and try to be of some help in this type of situation.
Explanation: The customer might be frustrated because of the question they're about to ask the employee. Maybe if the employee helps with the question there frustration will end. :)
