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ad-work [718]
3 years ago
8

Why is it so hard to please these teachers:(

Mathematics
2 answers:
Leno4ka [110]3 years ago
7 0

Answer:

I don’t even know man

Step-by-step explanation:

Temka [501]3 years ago
3 0
Who knows bruh, who knows
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Dale has a special deck of cards. Each card has a different rational number on it. The cards are 0.25, 4/5, 2/9, 0.48, and 8/11.
Mila [183]

Answer:

explain this question more clearer pls

Step-by-step explanation:

7 0
3 years ago
The width of a rectangle is 6 and two-thirds inches. The length of the rectangle is twice is width. What is the perimeter of the
Anna007 [38]
P = 2 x ( W+L)
P = 2 x (W + 2W)
p = 2 x 3W
P = 2 x 3(20/3) =40
3 0
3 years ago
3A(48+C)<br> What is the answer
Roman55 [17]

Answer:

144A+3AC

Step-by-step explanation:

I think you provided half of the problem. Because this does not make sense to any problem I can think of.

3 0
3 years ago
Help!! I need help!<br>​
Tasya [4]

Answer:

C

Step-by-step explanation:

-5x-49>113

    +49  +49

———————-

-5x>162

—-   ——

-5     -5

x<32.4

6 0
3 years ago
Solve for x: 2(x 3)2 − 4 = 0 Round your answer to the nearest hundredth. X = 4. 41, 1. 59 x = 1. 34, 5. 24 x = −1. 34, −5. 24 x
gladu [14]

The two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.

The standard form of the quadratic equation is,

ax^2+bx+c=0

Here, (<em>a,b,c</em>) are the real numbers and <em>x </em>is the variable.

To find the value of x, the following formula is used,

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The given equation is,

2(x+ 3)^2 - 4 = 0

To solve this equation, we need to apply some mathematical operations over it. Let's start with opening the brackets.

2(x+ 3)^2 - 4 = 0\\2(x^2+6x+9)-4=0\\2x^2+12x+14-4\\2x^2+12x+12=0\\x^2+6x+7=0

On comparing with standard equation we get,

a=1, b=6, c=7

Put this values in the above formula,

x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=-4.41,-1.59

Hence, the two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.

Learn more about the quadratic equation here;

brainly.com/question/1214333

5 0
2 years ago
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