make a probability tree it will really help so much
Width = 5
5x2 = 10 and the length would 13... which is 3 more inches than twice the width
Answer:
6 years
Step-by-step explanation:
So each person's age can be represented as a linear equation, since each year our age increases by 1. It can be represented in the slope-intercept form: y=mx+b. The slope in this case is going to be 1, since the time is going to be years, and each year everyone's age goes up by 1 (of course if you're still alive...) and y-intercept in this case represents their current age.
So the father can be represented as: y=x+38
The sons can be represented as: y = x+13 and y=x+5
The daughter can be represented as: y=x+8
So adding up all his children you get:
(x+13)+(x+5)+(x+8)
This gives you the equation:
3x+26
Now set this equal to the father's age to solve for x (in this context it's years)
3x+26=x+38
Subtract from both sides
2x+26=38
Subtract 26 from both sides
2x=12
Divide both sides by 2
x=6
So in 6 years the father will be the same age as his children put together
Answer: The correct option is
(D) 60.
Step-by-step explanation: Given that the number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively.
After Kaye gave Alberto 10 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 7:5.
We are to find the number of stamps that Kaye had more than Alberto.
Let the number of stamps Kaye and Alberto has are 5x and 3x respectively.
Then, according to the given information, we have
So, the number of stamps that Kaye had = 5 × 30 = 150
and
the number of stamps that Alberto had = 3 × 30 = 90.
Therefore, the number of stamps that Kaye had more than Alberto is
Thus, Kaye had 60 stamps more than Alberto.
Option (D) is CORRECT.
I think the thickness of the plank is 0.03m
