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cupoosta [38]
4 years ago
15

What best describes the solutions of

Mathematics
2 answers:
Natali [406]4 years ago
7 0
I do not see any trick of this question. Simply solve for x and it comes down to x < 7.
Iteru [2.4K]4 years ago
4 0
Let's solve this inequality.
1. Separate members with  x and without x in different sides:
-2+37>5x,
35>5x.
2. Rewrite it in reverse order:
5<35.
3. Divide by 5:
x<7 - all real numbers less than 7 are solutions.

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Please help is questions 1, 2, and 6! Please show work for brainliest!
Tema [17]

Answer:

Q1) 210

Q2) 198

Q6) 2.5 × base

Step-by-step explanation:

Q1) 9×(6+5+7) + 2(½×6×8)

= 162 + 48

= 210 cm²

Q2) (4+4+2+2+2+2+3+3) × 3²

= 22 × 9

= 198 ft²

Q6) parallel to base is a triangle

½ × 5 × base

= 2.5 × base cm²

5 0
4 years ago
If t is any real number, prove that 1+(tant)^2=(sect)^2
BlackZzzverrR [31]
1+\left(tant\right)^2=\left(sect\right)^2\\\\L=1+\left(\frac{sint}{cost}\right)^2=1+\frac{sin^2t}{cos^2t}=\frac{cos^2t}{cos^2t}+\frac{sin^2t}{cos^2t}=\frac{cos^2t+sin^2}{cos^2t}=\frac{1}{cos^2t}\\\\=\left(\frac{1}{cost}\right)^2=(sect)^2=R\\\\====================================\\\\\\tanx=\frac{sinx}{cosx}\\\\sin^2x+cos^2x=1\\\\secx=\frac{1}{cosx}
6 0
4 years ago
The life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed.
Anton [14]

Answer:

a) The evidence suggest the true mean life of a biomedical device > 5500

b) (5487.94, +∞)

c) There is evidence to support that the mean is equal to 5500

Step-by-step explanation:

Here we have

(a) To test the hypothesis we have the claim that the mean life of biomedical devices > 5500

Therefore, we put the null Hypothesis which is the proposition that a difference does not exist. That is

H₀:  μ = 5500

Therefore, the alternative hypothesis will be

Hₐ:  μ > 5500

The test statistic is then found by;

t=\frac{\bar{x}-\mu }{\frac{s }{\sqrt{n}}} =\frac{5617.8-5500 }{\frac{234.5 }{\sqrt{15}}} \approx 1.95

The P value from the T table at df = n - 1 = 15 - 1 = 14 is

0.025 < P < 0.05

The P value is given as 0.036 from the T distribution at 14 derees of freedom df

Therefore, since P < α or 0.05, we reject the null hypothesis. That is we fail to reject Hₐ:  μ > 5500. The evidence suggest the true mean life of a biomedical device > 5500

(b) The 95% confidence interval is given as

CI=\bar{x}\pm t_\alpha \frac{s}{\sqrt{n}}

Which gives    t_\alpha =  \pm2.145

CI=5617.8\pm 2.145 \times \frac{234.5}{\sqrt{15}}

The confidence interval of the lower bound on the mean is then

(5487.94, +∞)

c) From the above result, we find that the mean of 5500 is contained in the range of the lower confidence on the mean. We can therefore, accept the null hypothesis. That is there is evidence to support that the mean is equal to 5500.

6 0
3 years ago
Which linear function represents the line given by the point-slope equation y +1=-3(x–5)?
Tatiana [17]

Answer:

f(x)=-3x+14

Step-by-step explanation:

y +1=-3(x–5)

y +1=-3x+15

y= -3x+15-1

f(x) = -3x + 14

5 0
3 years ago
Read 2 more answers
0.3% of 460 plz is for tomorrow
DochEvi [55]

Answer:

1.38

Step-by-step explanation:


7 0
3 years ago
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