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Volgvan
3 years ago
6

Explain how do you solve an equation by using zero product property?

Mathematics
1 answer:
zloy xaker [14]3 years ago
6 0

Answer:

33333333333333333333333333333333333333

Step-by-step explanation:

You might be interested in
Is the one i picked right​
motikmotik
The arithmetic sequence formula should help you
An= A1+ (n-1)d or An= a + d(n−1)
An= the term that you want to find.
A1 = first term in the list of ordered numbers
n = the term position (ex: for 5th term, n = 5 )
d = common difference of any pair of consecutive or adjacent numbers
So, looking the 4 choices you have the only one that follow the sequence of the formula is C
I believe the one you choose is Fibonacci sequence.
There different number of sequences:
1- arithmetic sequence
2- geometry sequence
3- Fibonacci sequence
Each of that sequences have their own formula.
So, the answer it might be C
Hope that help you




The formula for the Arithmetic is:
An = A1 + F x ( n- 1)
I believe answer is C
Because the one you chose is
7 0
3 years ago
Please help! Which expression is equal to..?
Alenkasestr [34]

Answer:

A

Step-by-step explanation:

Before we can add the 2 fractions we require them to have a common denominator.

Multiply the numerator/ denominator of the first fraction by x

Multiply the numerator/ denominator of the second fraction by (x + 3)

= \frac{3x(x)}{x(x+3)} + \frac{(x-2)(x+3)}{x(x+3)}

Now simplify the numerator, leaving the denominator

= \frac{3x^2+x^2+x-6}{x(x+3)}

= \frac{4x^2+x-6}{x(x+3)} → A

5 0
3 years ago
Please help test due in 30 mins!
nikklg [1K]

Answer:

A is the answer

Step-by-step explanation:

3 0
3 years ago
In solving a fraction equation, John added the numerators of several fractions with unlike denominators. What should John have d
telo118 [61]
John should have found a common denominator.
3 0
3 years ago
Read 2 more answers
Evaluate it..........​
trasher [3.6K]

Answer:

the answer is \frac{1}{41} (23x-2ln(5sinx+4cosx))

Step-by-step explanation:

\int {\frac{3sinx+2cosx}{5sinx+4cosx} } \, dx

here,

a=3, b=2, c=5, d=4

M=\frac{ac+bd}{c^2+d^2 }=\frac{3*5+2*4}{5^2+4^2}=\frac{23}{41}

N=\frac{bc-ad}{c^2+d^2 }=\frac{2*5-3*4}{5^2+4^2}=\frac{-2}{41}

\int {\frac{3sinx+2cosx}{5sinx+4cosx} } \, dx=\int{\frac{\frac{23}{41}(5sinx+4cosx)-\frac{2}{41}(5cosx-4sinx)  }{5sinx+4cosx} }\,dx

=\frac{23}{41}\int\, dx -\frac{2}{41} \int{\frac{5cosx-4sinx}{5sinx+4cosx} }\, dx

=\frac{1}{41} (23x-2ln(5sinx+4cosx))

pls mark it as the brainliest

5 0
2 years ago
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