We can set Maggie's age to x
If her brother is six years younger than four times her age, than her brother must be equal to: 4x-6
Since the sum of their ages is 39, we can set up an equation.
(Sum of Maggie's age) + (sum of Maggie's brother's age) = 39
x + (4x -6) = 39
5x -6 = 39
5x = 45
x = 9 , Maggie's age is 9
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
5/6 is closest to 1 because it it 1/6 away from 1 and is 5/6 away from 0 and is 2/6 away from 1/2 (referring 1/2 as 3/6) Hope this helps!
Answer:
78.61 is greater than 78.6.
Step-by-step explanation:
Adding a zero to 78.6, resulting in 78.60, makes it easier to compare 78.6 and 78.61. 78.61 is greater than 78.6.
