I believe it is 4 my good sir
Answer:
Only the given table represents a function. Option 1 is correct.
Step-by-step explanation:
A relation is called a function, if there exist a unique value of y for each value of x. It means for each input there exist a unique output.
A function is always a relation but all relations are not function.
In the given table for each value of x, we have unique value of y, therefore the given table represents a function.
In second relation, at x=-2, the values of y are y=10 and y=-7. For single x, there are more than one value of y, therefore the second relation is not a function.
In third relation, at x=6, the values of y are y=-2 and y=1. For single x, there are more than one value of y, therefore the third relation is not a function.
Answer:
1. For a cube, volume = 
2. ![\sqrt[3]{volume}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bvolume%7D)
= edge
3. Volume of the cube = 216 so, the edge = ![\sqrt[3]{216}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216%7D)
= 6
4. 1st blank = 6
2nd blank = 6
3rd blank = 216
4th blank = 216
5. 6 is the edge
6. As the room is a square and we have to find the side
Area = 121
Edge = ![\sqrt[2]{121}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B121%7D)
= 11
If my answer helped, kindly mark me as the brainliest!!
Thank You!!
10x^4y^4+2x^6-15y^6-3x^2y^2
