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sasho [114]
2 years ago
15

Have a wonderful day lvu<3 free pts...... also if you go for biden plz dont come in saying trump sucks or sum like that ive b

een getting alot of that lately........ be safe :)
455+446=?
Mathematics
1 answer:
Morgarella [4.7K]2 years ago
4 0

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

➷ 455+446= 901

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ May ♡

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24 over 32 as an equivelent fraction
andrew-mc [135]
12/16,
6/8,
3/4, and
45/60

are all equivalent to 24/32.

Now that I've listed those four, there are
only an infinite number of others remaining.
4 0
3 years ago
1/6 (15a + 20b) = <br> distributive properties
valentina_108 [34]

Answer:

\frac{15a+20b}{6}     15a+20b/6

Step-by-step explanation:

\mathrm{Apply\:the\:fraction\:rule}:\quad \:a\cdot \frac{b}{c}=\frac{a\cdot \:b}{c}

7 0
2 years ago
I need help with this as well
xxTIMURxx [149]

Answer:

I think this is the answer

Area 77cm2

7 0
3 years ago
En una caja de cartón se empacan 400 latas de atún al acomodarlas resultan que caben 5 latas más a lo largo que a lo ancho y a l
Anvisha [2.4K]

Answer:

Hay 50 latas en total que tocan el fondo de la caja.

Step-by-step explanation:

Una caja de cartón es representada por un cuadrilátero, cuyas caras son rectángulos. Si la caja esta ocupada por completo, entonces la cantidad total de latas es representada por la siguiente expresión:

n_{V} = n_{w}\cdot n_{h}\cdot n_{l} (1)

Donde:

n_{V} - Total de latas de atún, adimensional.

n_{w} - Cantidad de latas de atún a lo ancho de la caja, adimensional.

n_{h} - Cantidad de latas de atún a lo alto de la caja, adimensional.

n_{l} - Cantidad de latas de atún a lo largo de la caja, adimensional.

De acuerdo con el enunciado, tenemos las siguientes relaciones:

n_{V} = 400 (2)

n_{l} = n_{w} +5 (3)

n_{h} = n_{w}+3 (4)

Si aplicamos estas fórmulas a (1), tenemos el siguiente polinomio de tercer orden:

n_{w} \cdot (n_{w}+5)\cdot (n_{w}+3) = 400

n_{w}\cdot (n_{w}^{2}+8\cdot n_{w}+15) = 400

n_{w}^{3}+8\cdot n_{w}^{2}+15\cdot n_{w} -400 = 0

Este polinomio se puede resolver por vía analítica por el Método de Cardano o por vía numérica, sus raíces son:

n_{w,1} = 5, n_{w,2} = -6.5+i\,6.144, n_{w,3} = -6.5-i\,6.144

En consecuencia, la única solución válida es n_{w} = 5 y las variables restantes son por (3) y (4):

n_{l} = 10 y n_{h} = 8

La cantidad de latas que tocan el fondo de la caja es igual al producto de la cantidad de latas a lo largo de la caja y la cantidad de latas a lo ancho de la caja, es decir:

n_{A} = n_{w}\cdot n_{l} (5)

n_{A} = (5)\cdot (10)

n_{A} = 50

Hay 50 latas en total que tocan el fondo de la caja.

4 0
2 years ago
What is the GCF of 28 and 72? Please explain if you can.
Minchanka [31]
72=1,72,2,36,3,24,4,18,6,12,8,9 28=1,28,2,14,4,7 So,the answer is 4
5 0
2 years ago
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