Answer:
x^(5/6) + 4(x^(7/3))
Step-by-step explanation:
Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )
Simplify x^(1/3) × (x^(1/2) + (2x)^2)
= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)
= x^(1/3+1/2) + 4(x^(1/3+2))
= x^(5/6) + 4(x^(7/3))
x^(1/3) is y such that y^3 = x
(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x
x^(1/2) = √2 = y such that y^2 = x
(2x)^2 = 4x^2
The answer is
12(2x-5)
good luckk
i hope i could help
Answer:
domain: (-∞,∞) x║x∈R
range: (-4,∞) y║y>-4
asympotote: (y=-4)
Step-by-step explanation:
Yes, I can solve that inequality.
Any value of ' r ' that's less than 1/3 is a solution.
