<em>Answer</em><em>:</em>
<h2>
<em>5</em></h2>
<em>-</em><em>1</em><em>0</em><em>=</em><em>m+</em><em>(</em><em>-</em><em>1</em><em>5</em><em>)</em>
<em>or,</em><em>-</em><em>1</em><em>0</em><em>=</em><em>m-15</em>
<em>or,</em><em>-m=</em><em>-</em><em>1</em><em>5</em><em>+</em><em>1</em><em>0</em>
<em>or,</em><em>-</em><em>m=</em><em>-</em><em>5</em>
<em>m=</em><em>5</em>
<em>Hope </em><em>it</em><em> helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
Order of operations is Parentheses, Exponents, Multiplication and Division (left to right), Addition and Subtraction (left to right)
7 + 6[-2] - 5
First, multiplication. Multiply 6 by -2. You get -12
7 - 12 - 5
Now, all that’s left is subtraction. Subtract from left to right, so subtract 7 and 12 first. 7-12= -5
-5 - 5
Now just solve the rest of it. -5 minus 5 is -10.
The final answer is -10
If you have any further questions feel free to ask.
Hope this helps.
Step-by-step explanation:
Let the two numbers be x and y
By the question
x + y = 87 ..... equation (I)
x - y = 65 ...... equation (II)
Now adding both equations we get
2x = 152
x = 152 / 2
Therefore x = 76
Putting x = 76 in equation i
76 + y = 87
y = 87 - 76
Therefore y = 11
The two numbers are 76 and 11.
Hope it helps :)
#1.
[4x = -12y + 16 and x + 3y = 4]
One answer
#2.
Here, y = 4x + 3
y - 4x = 3
Multiply by 2,
2y - 8x = 6
Compare with second equation,
6 ≠ 3
In short, System of Equation does not have any solution. [ Option D ]
#3.
2y=6
3x-6y=18
Divide first equation by 2: y=3
Substitute y=3 into second equation: 3x-6(3)=18
Solve for x: 3x=36 x=12
Therefore there is only one solution: x=12 y=3
#4.
y - 7x = -14
7y - 49x = -2
Rewrite the first equation as "y =" so that it can be substituted into the second equation and solve for x.
y = 7x - 14
7(7x - 14) - 49x = -2
49x - 98 - 49x = -2
-98 = -2
Since the variables cancel and the equation is not true there is no solution.
The lines are parallel and will not intersect.