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just olya [345]
3 years ago
6

Roger is buying a new pair of shoes for 25% off. If the original price of the shoes was $70.00, how much money is Roger saving o

n the shoes?
A. $52.50
B. $5.25
C. $17.50
D. $1.75
Mathematics
1 answer:
Kryger [21]3 years ago
5 0
10% is 7 dollars so 20% is 14 and have of 7 is 3.5 so it's 17.50
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You can buy 10 pounds of melons
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Multiple choice ! pls help
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The right answer is c
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Suzanne bought a sweater at the sale price of $25. The original cost of the sweater was $40. What percent represents that discou
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15/40 x 100 = 37.5
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Line E'F' has endpoints located at E'(1,0) and F'(1,3). Line EF was dilated by a scale of 1/2 from the orgin. Which statement de
Lerok [7]

Answer:

If line EF was dilated by a scale of 1/2 from the origin to get line E'F', then if line E'F' is dilated by a scale of 2 from the origin, EF is obtained. Also, the length of EF is double than the length of E'F'.

Dilation by a scale of 2 from the origin transforms point (x,y) into (2*x, 2*y)

E'(1,0) -> E(2,0)

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6 0
3 years ago
A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select
podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.626

The confidence interval is:

\overline{x} \pm M

In which \overline{x} is the sample mean while M is the margin of error.

The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.

This means that \overline{x} = 6.2

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.626\frac{2.1}{\sqrt{101}} = 2.626(0.21)

In which s is the standard deviation of the sample and n is the size of the sample.

Thus, the confidence interval is:

\overline{x} \pm M = 6.2 \pm 2.626(0.21)

And the correct answer is given by option c.

5 0
3 years ago
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