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taurus [48]
2 years ago
13

Hurry please ill give brainly

Mathematics
2 answers:
Ganezh [65]2 years ago
7 0

Answer:

\large\boxed{ \sf 16x+12}

<h3>Explanation:</h3>

\rightarrow \sf 4(5x+3)-4x

\rightarrow \sf 4(5x) +4(3)-4x

\rightarrow \sf 20x +12-4x

\rightarrow \sf 20x -4x+12

\rightarrow \sf 16x+12

Alex17521 [72]2 years ago
6 0

B).16x+12

Step-by-step explanation:

<h3><u>4(5+3)-4x</u></h3><h3>(20-4x)+12</h3><h3>(20+4x)+12</h3><h3>16x+12</h3><h3 />
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Please... ?
katrin [286]

Answer:

  • <em>The common ratio of the progression is 3/4</em>

Explanation:

A <em>geometric progression</em> is a sequence of terms in which the consecutive terms have a constant ratio; thus, each term is equal to the previous one multiplied by a constant value:

First\ term=a_1\\\\ Second\ term=a_2=a_1\times r\\\\ Third\ term=a_3=a_2\times r=a_1\times r^2\\\\n_{th}\ term=a_n=a_{n-1}\times r=a_1\times r^{n-1}

A<em> infinite geometric progression</em> may have a finite sum. When the absolute value of the ratio is less than 1, the sum of the infinite geometric progression has a finite value equal to:

  • S_{\infty}=\frac{a_1}{1-r}

Thus, the information given translates to:

a_1=5\\ \\ S_{\infty}=20=\frac{5}{1-r}

Now you can solve for the constant ratio, r:

1-r=\frac{5}{20}\\ \\ r=1-\frac{5}{20}\\ \\ r=\frac{15}{20}\\  \\ r=3/4

7 0
3 years ago
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The answer is -18%! Hope this helps :)
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3 years ago
How many angles must be supplementary with angle 14? 4 lines intersect to form 16 angles. The angles created, clockwise from top
trapecia [35]

Answer:

four

Step-by-step expif this is worng but i had a similar question and that as the answer

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Mandarinka [93]

It \: would \: take: \: 54 \div 36 = 1.5hrs
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Which of the following must be true about p?
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9514 1404 393

Answer:

  B, C, F, H

Step-by-step explanation:

When the function has end behavior that goes to opposite infinities, the degree must be odd, as here.

When the function goes to infinity with the same sign as the variable, then the leading coefficient must be positive, as here.

When the function crosses the y-axis at a negative value, the constant must be negative, as here.

When the function crosses the x-axis at a zero, the zero must have odd multiplicity, as for the zero x=1 here.

Choices B, C, F, H apply.

8 0
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