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taurus [48]
2 years ago
13

Hurry please ill give brainly

Mathematics
2 answers:
Ganezh [65]2 years ago
7 0

Answer:

\large\boxed{ \sf 16x+12}

<h3>Explanation:</h3>

\rightarrow \sf 4(5x+3)-4x

\rightarrow \sf 4(5x) +4(3)-4x

\rightarrow \sf 20x +12-4x

\rightarrow \sf 20x -4x+12

\rightarrow \sf 16x+12

Alex17521 [72]2 years ago
6 0

B).16x+12

Step-by-step explanation:

<h3><u>4(5+3)-4x</u></h3><h3>(20-4x)+12</h3><h3>(20+4x)+12</h3><h3>16x+12</h3><h3 />
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Help show works rep by step I’ll give brainly
masha68 [24]

Answer:

4 lbs left after 5 days

Step-by-step explanation:

First, you need to step up an equation!

You know that Soomin has a total of 20 pounds and that she's using it, so you are going to use subtraction.

She uses 3 1/5 pounds per day so you write:

20 - 3 1/5x

and you know that she wants to know how much she has left after 5 days so you replace the x with 5:

20 - (3 1/5) * 5

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8 0
2 years ago
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If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

5 0
3 years ago
N a survey, a group of students were asked their favorite sport. Eighteen students chose "other" sports. baseball: 40% football:
Paladinen [302]

Answer:

22.5%

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The total number of students in percentage terms is 100%

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3 years ago
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0.77875...

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