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Anvisha [2.4K]
3 years ago
12

What percent is 88 of 106?Show your work.

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
4 0
106 is a percentage of 88. Lets say x represents the percent.
The equation would be 88x=106.
We divide 88 on both sides to get x.
106/88 is around 1.2.
This is equal to 120%.
77julia77 [94]3 years ago
3 0
88/106 x 100
.830188679 x 100
83.02%

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Which would the phrase "two times the quotient of a number and 3" look like as a variable expression?
Naya [18.7K]
2 n/3 would be the closest answer although it looks as if the 2 is supposed to be multiplied by n/3 which would lead me to write it as 2(n/3)

6 0
3 years ago
Round this whole number Round 10,652 to the nearest ten.
ValentinkaMS [17]

Answer:

10650

Step-by-step explanation:

3 0
3 years ago
Use the graph of f(x) below to estimate the value of f '(3):
klio [65]
Well, looking at the graph, notice, its vertex is at 0,9, and it passes through the points -3,0 and 3,0, so hmm let's use 3,0, to get the equation of f(x)

\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------

\bf vertex~(0,9)~
\begin{cases}
h=0\\
k=9
\end{cases}\implies y=a(x-0)^2+9
\\\\\\
\textit{we also know that }
\begin{cases}
x=3\\
y=0
\end{cases}\implies 0=a(3-0)^2+9
\\\\\\
-9=9a\implies \cfrac{-9}{9}=a\implies -1=a\quad thus\quad \boxed{y=-x^2+9}
\\\\\\
\left. \cfrac{dy}{dx}=-2x \right|_{x=3}\implies -6
3 0
3 years ago
Read 2 more answers
Identify each line or segment that intersects ⊙ S.
Delicious77 [7]

Answer:

AC, CE, AB, and AS

I belive those are your answers

7 0
3 years ago
Read 2 more answers
A junk box in your room contains fourteen old​ batteries, seven of which are totally dead. You start picking batteries one at a
MrMuchimi

Answer:

A junk box in your room contains fourteen old​ batteries, seven of which are totally dead.

So, number of good batteries = 14-7=7

a) The first two you choose are both good. ​

There is a 7/14 chance that we will pick a good battery.

Now there are 13 batteries left and out of that there are only 6 good ones remaining, so this becomes 6/13.

So, combined probability is = \frac{7}{14}\times \frac{6}{13}

= 0.23

b) At least one of the first three works.

\frac{7}{14} \times \frac{6}{13} \times \frac{5}{12} =0.096

And at least one is good battery, we get : 1-0.096=0.904

​c) The first four you pick all work.

There is a probability of 7/14 for the first one to work, 6/13 for the second, 5/12 for the third and 4/11 when the fourth is good, combined we get by multiplying all:

\frac{7}{14}\times \frac{6}{13}\times \frac{5}{12}\times \frac{4}{11}=0.0344

d) You have to pick five batteries to find one that works.

This condition means that we pick 4 bad batteries and 1 good battery.

The probability of picking 4 bad batteries is -

\frac{7}{14}\times \frac{6}{13}\times \frac{5}{12}\times \frac{4}{11}=0.0344

Since there are 7 good batteries remaining in 10 batteries so we will multiply 7/10 in 0.0344 to know the fifth one that finally works.  

This becomes = 0.0344\times0.7=0.024

5 0
3 years ago
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