A = 2/3......remainder 1/3
B = 1/4(1/3) = 1/12
2/3 + 1/12 = 8/12 + 1/12 = 9/12 reduces to 3/4 remainder 1/4
C = 1/3(1/4) = 1/12
3/4 + 1/12 = 9/12 + 1/12 = 10/12 reduces to 5/6 remainder 1/6
so Gana gets 1/6
check...
adam gets 2/3 or 8/12
ben gets 1/12
cathy gets 1/12
Gana gets 1/6 or 2/12
added = 12/12 or 1....correct
Dana gets 1/6 <==
Answer:
Wait wattttttttt?
Step-by-step explanation:
<h3>
Answer: Diverges</h3>
This series diverges by the limit test (some books may call it the nth term test).
Recall the limit test is the idea if the sequence doesn't converge to 0, then the series diverges.
In this case, the sequence converges to n/(7n) = 1/7 since all we are about are the leading terms when n gets very large.
After some very large n value, we're effectively adding on 1/7 or very close to it, each time. The infinite sum does not approach a fixed value. It keeps growing forever.
The construction is missing, so i have attached it.
Answer:
Use the incenter to determine the center to construct the circle.
Step-by-step explanation:
From the attached image, we can see that the 3 bisector of the three interior angles in the triangle intersect at a point. This point is known as the incentre of the triangle.
Now, to draw an inscribed circle inside the triangle, we will draw a perpendicular line from the incentre to any of the 3 sides and we will use the incentre as centre to draw the circle to touch each of the 3 perpendicular points.
Answer:
40
Step-by-step explanation: