Part A. To solve for the distance travelled during the
interval, all we have to do is to plug in values of t = 3 and t = 3.5 in the
equation and the difference would be the answer:
when t = 3: s = 16 (3)^2 = 144 m
when t = 3.5: s = 16 (3.5)^2 = 196 m
Therefore the distance travelled within the interval is:
196 m – 144 m = 52 m
<span>Part B. The velocity is calculated by taking the 1st
derivative of the equation. v = ds / dt</span>
s = 16 t^2
ds / dt = 32 t = v
when t = 3: v = 32 (3) = 96 m / s
when t = 3.5: v = 32 (3.5) = 112 m / s
Therefore the average velocity is:
(96 + 112) /2 = 104 m / s
Part C. We can still use the formula v = 32 t and plug in
the value of t = 3
v = 32 t = 32 (3)
v = 96 m / s
<span> </span>
Answer: (x^2)/16 + (y^2)/25 = 1
Step-by-step explanation:
According to the problem we can figure out that the center of the ellipse is (0,0).
Since the foci is (0,3) and (0,-3) we know that the value of c is 3. The major vertices are (0,5) and (0,-5) so the value of a is 5.
If we put this into the equation a^2=b^2 + c^2, we get 25=9+ b^2
We get b^2 is 16
Now since we know that the ellipse is vertical because the x value didn’t change, we know that the b^2 value comes first in the equation. Then the a^2 value which is 25.
Answer:
2 per balloon
Step-by-step explanation:
Dozen = 12
Answer:
6.5
Step-by-step explanation:
Answer: 45.58 degrees
Step-by-step explanation:
