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ziro4ka [17]
3 years ago
14

Find the solution for the equation from the numbers 29.6, 31.4, 42.4, or 18.6. t + 32.4 = 62

Mathematics
2 answers:
Burka [1]3 years ago
8 0

The answer is!!!!!

t = 26.9 ^-^

Sav [38]3 years ago
4 0
You want to subtract 32.4 from 62 to get the value of t.
62- 32.4= 29.6
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Double my number<br> add four<br> subtract my number <br> and<br> subtract three
Elena L [17]
X is your number

double it means 2 times x or 2x

add 4
2x+4

subtract my number
2x+4-x=x+4

subtract 3

x+4-3=x+1

the result is x+1 or your number plus 1
3 0
4 years ago
What shape is this cross-section?​
melisa1 [442]

Answer:

Square

Step-by-step explanation:

From what it looks like I think it is a square

6 0
3 years ago
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In a survey, 11 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped
pickupchik [31]

Answer:

The population standard deviation is not known.

90% Confidence interval by T₁₀-distribution: (38.3, 53.7).

Step-by-step explanation:

The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus 11 - 1 = 10.

Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,

  • The area to the left of the lower end of the interval shall be 1/2 \cdot (1 - 0.90)= 0.05.
  • The area to the left of the upper end of the interval shall be 0.05 + 0.90 = 0.95.

Look up the t-score of the upper end on an inverse t-table. Focus on the entry with

  • a degree of freedom of 10, and
  • a cumulative probability of 0.95.

t \approx 1.812.

This value can also be found with technology.

The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:

\displaystyle t \cdot \frac{s_{n-1}}{\sqrt{n}},

where

  • t is the t-score at the upper end of the interval,
  • s_{n-1} is the unbiased estimate for the standard deviation, and
  • n is the sample size.

For this confidence interval:

  • t \approx 1.812,
  • s_{n-1} = 14, and
  • n = 11.

Hence the width of the 90% confidence interval is

\displaystyle 1.812 \times \frac{14}{\sqrt{10}} \approx 7.65.

The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:

(38.3, 53.7).

5 0
3 years ago
Which expressions are equivalent to 6y-18h?
lukranit [14]

First you had to rewrite the problem with eighteen as the three times six is equal to eighteen.

=6y-3*6h

Then you factor it out by the common term of six.

=6(y-3h)

Final answer: \boxed{6(y-3h)}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

5 0
3 years ago
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If the 3rd and 9th term of an ap are 4 and -8 respectively then which term of AP is zero​
Anon25 [30]

Answer:

fifth term

Step-by-step explanation:

The n th term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

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a₁ + 2d = 4 → (1)

a₁ + 8d = - 8 → (2)

Subtract (1) from (2)

6d = - 12 ( divide both sides by 6 )

d = - 2

Substitute d = - 2 into (1)

a₁ + 2(- 2) = 4

a₁ - 4 = 4 ( add 4 to both sides )

a₁ = 8

Thus equating the n th term formula to zero and solving for n

8 - 2(n - 1) = 0 ( subtract 8 from both sides )

- 2(n - 1) = - 8 ( divide both sides by - 2

n - 1 = 4 ( add 1 to both sides )

n = 5

The fifth term is equal to zero

8 0
3 years ago
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