Answer:
do you have any options for this question just to check??
X=-b/2a=4/14=2/7
Plug this value back into the function to find the corresponding Y value
Lets call those two unknown numbers a, b and write the info in the problem as equations:
a*b = 30
a + b = 40
lets solve for a in the second equation and substitute in the first:
<span>a + b = 40
</span>a = 40 - b
therefore:
<span>a*b = 30
</span>(40 - b)b = 30
40b - b^2 = 30
b^2 - 40b + 30 = 0
if we apply the general quadratic equation to solve we have:
b = (40 +- √(1600 - 120))/2
b = (40 +- √(1480<span>))/2
</span>b = (40 +- 38.47)/2
There are two solutions:
<span>b1 = (40 + 38.47)/2
</span><span>b1 = 39.24
b2 = (40 - 38.47)/2
</span>b2 = 0.765
lets use the second solution <span>b2 = 0.765, and substitute in the first equation to find a:
</span><span>a*b = 30
</span>a*0.765 = 30
a = 30/0.765
a = 39.216
so the numbers are 39.216 and 0.765
Answer:
Total monthly cost (x) = $39 + ($0.07/min)x
Step-by-step explanation:
The y-intercept is $39. The slope is ($0.07/minute)x, where x is the number of talk minutes. Thus:
Total monthly cost (x) = $39 + ($0.07/min)x, where x is the number of talk minutes.
Smaller Angle: 49 degrees
Bigger Angle: 131 degrees
Note that supplementary angles add up to be 180 degrees. Knowing this and the information provided in the question, we can use the following system of equations:
x + y = 180 (showing they both add up to 180)
x + 82 = y (to show one angle is 82 more than the other)
We can use the substitution method to solve. Since the second equation ends in "= y" we can substitute the value of it into y for the first equation.
x + y = 180; x + 82 = y ==> x + (x + 82) = 180
And now, solve for x:
x + (x + 82) = 180
x + x + 82 = 180 > combine like terms
2x + 82 = 180
2x = 98
x = 49
So now we have the value for one of the angles! Remembering that the other angle is 82 degrees bigger, dd 49 + 82, which equals 131.
So, our two angle values are 131 and 49! This is correct since both angle measures add up to be 180, which also makes them supplementary!
