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Katena32 [7]
3 years ago
15

14 pies eaten in 2 minutes what's the rate

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

7:1

Step-by-step explanation:

idrk but here                                                              

anyanavicka [17]3 years ago
4 0

Answer:

7 pies per minutes

Step-by-step explanation:

14/2 =7

so 7 is your number of pies eaten in one minutes

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Which letters have rotational symmetry ? answers : W , K, Y , O , P , Z
nirvana33 [79]
O definitely does. I think Z and W do as well.

Y, K and P don't because they can't be rotated and map onto themselves.
4 0
3 years ago
There are 9 apples. there are 6 fewer apples than oranges. how many oranges are there
Juliette [100K]

Answer:

15

Step-by-step explanation:

9 apples plus 6 more is 15 oranges

5 0
3 years ago
Read 2 more answers
PLs help
Pavel [41]

A) The hypotenuse is the longest side of the triangle .In the figure EG is the hypotenuse.The given angle is <G=40 degrees.The side adjacent is FG= 10 units.

The question is asking us to find the trigonometry ratio which will  help us find EG.We can use cos  as cos is ratio of adjacent and hypotenuse.

cos 40=\frac{10}{Hypotenuse EG.}

B) Cos  40 =0.766.

Substituting tan40 value we have:

0.766=\frac{10}{EG}

EG=13.05.

C)Sum of angles in  triangle is 180.

<E+<F+<G=180

<E+90+40=180

<E+130=180

<E=50 degrees.

D) Tan  40=\frac{EF}{10}

EF=8.39

E) Area of triangle EFG= \frac{1}{2}x base x height.

A rea of the triangle = \frac{1}{2}x8.39x13.05

Area= 54.75 square units.





5 0
3 years ago
Answer asap!!! which equation could be used to find the perimeter of a rectangle that has a width of 10 inches and a length of 2
Arlecino [84]

Answer:

d. p = 2*20 + 2*10

Step-by-step explanation:

You know to find the perimeter, just add side + side + side + side.

And two pairs of sides on a rectangle are congruent, so the missing side lengths based on the width and length, will be 20 & 10.

So add 20 + 20 + 10 + 10.

To simplify this, say 2*20 and 2*10. And then add them.

So it is D

5 0
3 years ago
The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we
Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

            Sigma, σ = 0.200 kg

            Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13 $

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

 Test statics :

   $Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}} $

  $Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}} $

          $=\frac{1.82}{0.04}$

          = 45.5  

P-value = 2 x P(Z > 45.5)

            = 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value  < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0
3 years ago
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