Question

2) Suppose 120 people are surveyed and asked about their eating habits. 50 people

Answer 1

Answer:

1/6

Step-by-step explanation:

Given that :

Total surveyed (u) = 120

n(Cane's chicken fingers) = 50

n(Layne's chicken fingers) = 80

n(do not like either) = 10

a)

What is the probability that someone surveyed likes both Raising Cane's and Layne's chicken fingers?

n(Cane's n Layne's) = 20

u = 120

P = required outcome / total possible outcomes

P(Layne's and Cane's chicken) = [n(Cane's n Layne's)/ u]

= 20 / 120

= 1/6