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Nikolay [14]
2 years ago
9

Find the value of y in the following expression if x = 5 and type the result in the empty box.

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
3 0

Answer:

3.4 is the answer i think

Step-by-step explanation:

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Need help and please explain how you got your answer I want to know for next time.
Tatiana [17]

Answer:

(b)

student can choose none or some

5 0
3 years ago
60 POINTS + BRAINLIEST
Nitella [24]

Answer:

C

Step-by-step explanation:

By tracing the figure, we see that we go around a semicricle twice and go in a straight path twice. So the perimeter of this figure consists of two semicircles and two line segments, hence the answer is C.

3 0
3 years ago
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How many ways can 7 books be arranged on a shelf 5 at a time?
aliya0001 [1]
Symbolically, write this:

   C
7     5.  Know how to evaluate that?


C stands for "combination."
5 0
3 years ago
You are asked to do a study of shelters for abused and battered women to determine the necessary capacity in your city to provid
ohaa [14]

Answer:

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

274 shelters will be needed.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 250, \sigma = 75

If the city’s shelters have a capacity of 350, will that be enough places for abused women on 95% of all nights?

What is the percentile of 350?

This is the pvalue of Z when X = 350.

Z = \frac{X - \mu}{\sigma}

Z = \frac{250 - 150}{75}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082.

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

If not, what number of shelter openings will be needed?

The 95th percentile, which is X when Z = 1.645. So

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 150}{75}

X - 150 = 1.645*75

X = 274

274 shelters will be needed.

5 0
3 years ago
Simplify 2(4+8)÷2(8+8)​
inna [77]

192.

2(8+4)÷2(8+8) = 1(4+8)×(8+8)

1×12×16=192.

6 0
3 years ago
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