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-BARSIC- [3]
3 years ago
5

A catering company’s recipe for salad uses a ratio of 2 cups of dressing to 12 cups of vegetables. (a) Mrs. Roberts simplified t

his ratio to 2:6. Explain/show how you know she is incorrect. Can you tell where she might have made a mistake while simplifying?
Mathematics
2 answers:
rodikova [14]3 years ago
8 0
The ratio should be 1:6 seeing that every 1 cup of salad dressing there are 6 cups of vegetables
SVETLANKA909090 [29]3 years ago
8 0

A catering company’s recipe for salad uses a ratio of 2 cups of dressing to 12 cups of vegetables. (a) Mrs. Roberts simplified this ratio to 2:6. Explain/show how you know she is incorrect. Can you tell where she might have made a mistake while simplifying?

Solution:

So, A catering company’s recipe for salad uses a ratio of 2 cups of dressing to 12 cups of vegetables.

Ratio of dressing:vegetables=2:12.

Let us divide 2 and 12 by 2

Ratio of dressing: vegetables= \frac{2}{2} : \frac{12}{2}

So, finally we get ratio=1:6 and not 2:6. The mistake is in this step while simplifying.

So, Simplified Ratio of dressing:vegetables=1:6.


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A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
amm1812

Answer:

6546 students would need to be sampled.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.

This means that n = 200, \pi = \frac{118}{200} = 0.59

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?

n students would need to be sampled, and n is found when M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.59*0.41}{n}}

0.01\sqrt{n} = 1.645\sqrt{0.59*0.41}

\sqrt{n} = \frac{1.645\sqrt{0.59*0.41}}{0.01}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.59*0.41}}{0.01})^2

n = 6545.9

Rounding up:

6546 students would need to be sampled.

3 0
2 years ago
What is true about the dilation? A large parallelogram is the pre-image and a smaller parallelogram is the image. It has a scale
kotegsom [21]

Answer:

- It is a reduction with a scale factor between 0 and 1.

- It is an enlargement with a scale factor greater than 1.

Step-by-step explanation:

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2. In dilation, to obtain the new dimensions of the image you must multiply the dimensions of the original image by a number called "Scale factor".

3. When the scale factor is greater than 1 it is an enlargement and when this is between 0 and 1, it is a reduction.

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2 years ago
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Answer:

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Given the pair of simultaneous equation:
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3 years ago
Evaluate a+b for a=-17 and b=8
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