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3 years ago

Factor the sum or two cubes. X-3^3+8

Mathematics

1 answer:

Whitepunk [10]3 years ago

8 0

Answer:

[X-1]^3

Step-by-step explanation:

X-3^3+8

8 is 2^3

X-3^3+ 2^3

[(X-3)+2)]^3 = [X-3+2]^3 = [X-1]^3

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(2x-7)-(4x^2+6x-3)+(x^2+4)

masha68 [24]

Answer:

$-3x^2-4x$

Step-by-step explanation:

Simplify:

$\left(2x-7\right)-\left(4x^2+6x-3\right)+\left(x^2+4\right)$

$=2x-7-\left(4x^2+6x-3\right)+x^2+4$

Group same factor:

$=-\left(4x^2+6x-3\right)+x^2+2x-7+4$

Add :

$=-\left(4x^2+6x-3\right)+x^2+2x-3$

Apply the distributive law: -(a+b) = -a - b

$-\left(4x^2+6x-3\right)=-4x^2-6x+3$

$=-4x^2-6x+3+x^2+2x-3$

Group same factor:

$=-4x^2+x^2-6x+2x+3-3$

Subtract:

$=-4x^2+x^2-6x+2x$

Add:

$=-3x^2-6x+2x$

Group same factor:

$=-3x^2-4x$

Hence answer = $-3x^2-4x$

<u><em>~lenvy~</em></u>

8 0

2 years ago

Find the inverse of the equation y=2/3x-6

nlexa [21]

Answer:

Step-by-step explanation:

<h3> your answer is y = 3x+6/2</h3>

<h3> <em>Hope </em><em>it </em><em>helps.</em><em>.</em><em>.</em></h3>

5 0

3 years ago

Read 2 more answers

If a = -2, b = 6, and c = -5, find the value of a(3a² + 2ac)

sp2606 [1]

(-2)(3*4+2(-2)(-5)) = -2(12+20) = -2(32) = -64

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4 years ago

Describe a diagram of a pair of triangles that share a common angle and a common side.

Delicious77 [7]

Answer:

uploaded in the attachment

Step-by-step explanation:

if u see the diagram, there are 2 triangles in it ABC and ABD.

the common side for these pair of triangles is AB.

common angle is angle BAC.
therefore, these triangles share a common side AB and a common angle BAC.

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3 years ago

What solid figure has eight vertices?

ahrayia [7]

Rectangular prism the two square on the end have 4 vertices each

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3 years ago