Answer:
2). As x-> -∞, f(x)->∞
As x-> ∞, f(x)-> -∞
5). As x-> -∞, f(x)-> -∞
As x-> ∞, f(x)-> ∞
3). As x-> -∞, f(x)-> -∞
As x-> ∞, f(x)-> ∞
6). As x-> -∞, f(x)-> ∞
As x-> ∞, f(x)-> ∞
Step-by-step explanation:
I just watched a quick video so you can't completely trust me, but i tried my best. Hopefully someone more trustworthy for this comes in.
To find the cofactor of
![A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%265%263%5C%5C-7%264%26-1%5C%5C-8%262%261%5Cend%7Barray%7D%5Cright%5D)
We cross out the Row and columns of the respective entries and find the determinant of the remaining 
matrix with the alternating signs.
Therefore in increasing order, we have;
Answer:
(-3.07, 11.07)
Step-by-step explanation:
Given that a sports writer wished to see if a football filled with helium travels farther, on average, than a football filled with air. To test this, the writer used eighteen adult male volunteers. These volunteers were randomly divided into two groups of nine subjects each.
Group Group One Group Two
Mean 300.00 296.00
SD 8.00 6.00
SEM 2.67 2.00
N 9 9
The mean of Group One minus Group Two equals 4.00
standard error of difference = 3.333
df = 16
t = 1.2000
Margin of error = 3.3333* t critical = 3.3333*2.121
95% confidence interval of this difference: From -3.07 to 11.07
Answer: Harry Potter
Step-by-step explanation:
