Answer:
y = -5/3x -7
Step-by-step explanation:
If lines are parallel they have the same slope m = -5/3. Just need to figure out the new y-intercept going through the point (-9, 8).
y = mx + b
8 = -5/3(-9) + b
8 = 15 + b
b = -7
Now use m and b to form new equation of parallel line.
y = mx + b
y = -5/3x -7
Answer:
It must be A i mean i worked it out for a few so thats what i came up with
Step-by-step explanation:
<em><u>Question:</u></em>
Geoffrey is evaluating the expression (-3)^3(2^6)/(-3)^5(2^2) as shown below.
(-3)^3(2^6)/(-3)^5(2^2) = (2)^a/(-3)^b = c/d
What are the values of a, b, c, and d?
<em><u>Answer:</u></em>
<em><u>The values are a = 4, b = 2, c = 16, d = 9</u></em>
<em><u>Solution:</u></em>
Given that,
Geoffrey is evaluating the expression
He is evaluating as shown below:
From given,
Use the law of exponent
Therefore,
Thus,
a = 4
b = 2
Simplify further
Thus,
c = 16
d = 9
Thus values are a = 4, b = 2, c = 16, d = 9
Answer:
The slope line will change from negative to positive.
Answer:
mu = x√P(x) - £
£ = x√P(x) - xP(x)
Step-by-step explanation:
We have two equations there. Laying them simultaneously, we can derive the formula for "mu" and sigma. Let sigma be "£"
Equation 1
mu = £[xP(x)]
Equation 2
£^2 = x^2 P(x) - (mu)^2
Since we have sigma raised to power 2 (that is sigma square), we find sigma by square rooting the whole equation.
Hence sigma is equal to
[x√P(x) - mu] ...(3)
Since mu = xP(x), we substitute this into equation (3) to get
Sigma = x√P(x) - xP(x)
mu = x√P(x) - £
