How do u do this ? i am so confused and need help

Mathematics

1 answer:

Inessa [10]3 years ago

4 0

For question 9 - It is stating that AE is equal to 38. So the length of the entire line is 38. We then need to look at which figures are actually useful to us, which in this case is AC which is 10. Therefore the answer is as simple as 38-10, which gives us an answer of 28 for the other half of the line, notated as CE.

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The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and

strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

X ~ N ( u , s /√n )

Where

s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )

= P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1

7 0

3 years ago

A. Independent B. Inconsistent C. Equivalent D. Consistent

tangare [24]