Answer:
( 0.6 t^2 + 3t + 11 ) cm
Step-by-step explanation:
dh/dt = 1.2t + 3
at t = 0, h = 11 cm
(a)
dh / dt = 1.2 t + 3
dh = (1.2 t + 3) dt
integrate on both sides
h = 0.6 t^2 + 3t + c .... (1)
where c is the integrating constant
put t = 0
11 = c
Put in equation (1) , we get
h = ( 0.6 t^2 + 3t + 11 ) cm
Thus, teh height of tree after t years is given by
( 0.6 t^2 + 3t + 11 ) cm.
-8, -19, -30, -49 , -60
<u>Step-by-step explanation:</u>
Here we have the following sequence :
-8, -19, -30, _ , _
- First term of sequence is -8 .
- Second term of sequence is -19 :

- Third term of sequence is -30 :

- Fourth term of sequence is :

- Fifth term of sequence is :
Following sequence was an AP( Arithmetic Progression ) with first term as -8 i.e.
and common difference
having general equation as :
.
Answer: x < 11.9
Step-by-step explanation:
Answer:
1(5/16)=1.3125
7(5/16)=7.3125
26(5/16)=26.3125
Step-by-step explanation:
Given that 5/16=0.3125, the mixed fraction 1(5/16)=1+(5/16)=1+0.3125=1.3125
Also, 7(5/16)=7+(5/16)=7+0.3125=7.3125
Furthermore,
26(5/16)=26+(5/16)=26+0.3125=26.3125
In the same vein, given that 4/15=0.266
1(4/15)=1+(4/15)=1+0.266=1.266
17(4/15)=17+(4/15)=17+0.266=17.266
23(4/15)=23+(4/15)=23+0.266=23.266