Which expression is equivalent to 3(7x

Sam wants to fence his rectangular garden plot along its length on the front side. The perimeter of the plot is 24 meters, and i

Black_prince [1.1K]

Question is Incomplete;Complete question is given below;

Sam wants to fence his rectangular garden plot along its length on the front side. The perimeter of the plot is 24 meters, and its length is 3 times its width. If x is the length and y is the width of the plot, set the equations of the system. Solve and determine the values of x and y. If the cost of fencing is $25 per meter, how much does Sam need to spend on fencing?

Answer:

Length of the plot $(x)$ is 9 meter and width of the plot $(y)$ is 3 meter.

Sam need to spend $225 on fencing.

Step-by-step explanation:

Given;

Perimeter of the plot =24 m

Length of the plot is denoted ' $x$ '

Width of the plot is denoted by $'y'$

Cost of Fencing = $25 per meter.

We need to find the the values of x and y.

Also we need to find how much does Sam need to spend on fencing.

Solution:

Now given that;

length is 3 times its width.

so we get;

$x=3y$

Now we know that;

Perimeter of the rectangle is equal to 2 times sum of its length and width.

framing in equation form we get;

$24=2(x+y)$

But $x=3y$

so we get;

$24 =2(3y+y)\\\\24=2(4y)\\\\24=8y$

Dividing both side by 8 we get;

$\frac{24}{8}=\frac{8y}{8}\\\\y =3\ m$

Now width of the plot = 3 meter

Length of the plot $x=3y=3\times3= 9\ m$

Hence Length of the plot $(x)$ is 9 meter and width of the plot $(y)$ is 3 meter.

Now given that;

Sam wants to fence his rectangular garden plot along its length on the front side.

So we can say that;

Length to be fenced = 9 m

Cost of fencing = $25/meter

Cost of fencing the garden = $9\times 25= \$225$

Hence Sam need to spend $225 on fencing.

3 0

4 years ago

Which rational number is multiplied by 64 to get the product - 49?

Volgvan

Answer:

-.765625

Step-by-step explanation:

i took -49 and divided it by 64 to get the answer!

5 0

3 years ago

Use unit multipliers to convert 123 pounds per mile to ounces per centimeter. There are 5,280 feet in 1 mile. There are 16 ounce

gregori [183]

A unit multiplier is a conversion factor of value 1 that we can use to convert quantities.
We want to convert 123 pounds per mile to ounces per centimeter.
First, we are going to express the quantity to convert as a fraction:
123 pounds per mile= $123 \frac{pounds}{mile}$

Next, we are going to find our multipliers:
- We know for our problem that there are 5,280 feet in 1 mile, so our first multiplier will be: $\frac{1mile}{5280ft}$
- We also know that there are 16 ounces in 1 pound, so our second multiplier will be: $\frac{16ounces}{1pound}$
- We know that there are 12 inches in 1 foot, so our third multiplier will be: $\frac{1ft}{12in}$
- We know that t<span>here are approximately 2.54 cm in 1 inch, so our fourth multiplier will be: </span> $\frac{1in}{2.54cm}$

Now we can put all our multipliers together:
$123 \frac{pounds}{mile} * \frac{1mile}{5280ft}*\frac{16ounces}{1pound}* \frac{1ft}{12in}*\frac{1in}{2.54cm}=0.01 \frac{ounces}{cm}$

We can conclude that the answer is 0.01

3 0

4 years ago

HAPPY APRIL FOOLS- CAN ANYBODY ANSWER MY QUESTION---------

Bogdan [553]

This is an interesting question. Wish there were more questions of this kind.

This question helps us recognize the use of the vertex form of a quadratic expression/function.

The vertex form is in the form
$f(x)=y=a(x-h)^2+k$

The extreme value of the function occurs when x=h, i.e. when the first term vanishes, which leaves the value of the function equal to k. I.e. the vertex of the function is at (h,k).

For example, when
f(x)=5(x-4)^2+7
at x=4, f(4)=5(4-4)^2+7=5(0)+7=7,
in other words, f(x) is at its minimum when x=4, with a value of 7,
even simpler, the vertex of the function is at (4,7).

How do we know if it is a maximum or minimum?

If the first parameter "a" is positive, then at any other value than x=h, the function has a greater value than the vertex, hence a>0 => minimum.
Similarly, if the first parameter "a" is negative, then whenever x does not equal h, the value of the function is smaller, hence a<0 => maximum.

For example, with f(x)=5(x-4)^2+7, a=+5 >0, so (4,7) is a minimum.
Check: f(0)=5(0-4)^2+7=16+7=23 > 7, or (0,23) verifies that (4,7) is a minimum.

For given situations A, B, C, & D, we see that only one function is in the vertex form, i.e. y=a(x-h)+k, namely situation B
B. y=-3(x-2)^2+5, where a=-3, h=2 and k=5.
This means that the function has a maximum at the vertex (2,5). It has a maximum because a=-3 < 0, as discussed above.

Oh yes, enjoy the rest of April Fools Day! lol

4 0

3 years ago

A plumber charges $50 for a service call plus $80 per hour. If she spends no longer than 8 hours a day at any one site, find a l

Paha777 [63]

Answer:

$C(t)=80t+50, \text{ for }t\leq 8$ .