
Given that,
In <u>triangle TPQ, </u>
As it is given that, <u>RS || PQ</u>
So, it means
⇛∠TRS = ∠TPQ [ Corresponding angles ]
⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

<u>Now, We know </u>
Area Ratio Theorem,
This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.





st + 3t = 6 for s
Subtract 3t to both sides
st + 3t - 3t = 6 - 3t
Simplify
st = 6 - 3t
Divide both sides by t
st/t = (6-3t)/3
simplify
s = 6/3 - 3t/3
s = 2 - t
notice that the denominator can be factored into (x-3)(x+3).
Now you can cross out (x - 3) from the numerator and denomiantor resulting in a simplified fraction of 
Plug the limit value (which is 3) into the simplified fraction.
Answer: 
For this case we have the following expression:

The terms are not similar, so they cannot be added.
<em>Examples of similar terms:</em>

Then, the expression given can only be rewritten as:

This is taking common factor 2 to both terms.
Answer:

The first equation tells you that
. If you substitute this expression for
in the second, we have

And we can deduce 