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ArbitrLikvidat [17]
3 years ago
7

I need help with this math problem -15x=0

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0
Divide each term by -15 and simplify.


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12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

3 0
2 years ago
Solve st + 3t = 6 for s
vaieri [72.5K]

st + 3t = 6 for s

Subtract 3t to both sides

st + 3t  - 3t = 6 - 3t

Simplify

st = 6 - 3t

Divide both sides by t

st/t = (6-3t)/3

simplify

s = 6/3 - 3t/3

s = 2 - t


6 0
3 years ago
The limit as x-approaches 3 of f(x) is x-3 over x squared -9
Luden [163]

notice that the denominator can be factored into (x-3)(x+3).

Now you can cross out (x - 3) from the numerator and denomiantor resulting in a simplified fraction of \frac{1}{x+3}

Plug the limit value (which is 3) into the simplified fraction.

Answer: \frac{1}{6}

4 0
3 years ago
What is the sum of 2x^2 and 2x^3
jeyben [28]

For this case we have the following expression:

2x ^ 2 + 2x ^ 3

The terms are not similar, so they cannot be added.

<em>Examples of similar terms:</em>

x ^ 3 + x ^ 3 = 2x ^ 3\\3x ^ 4 + 2x ^ 4 = 5x ^ 4

Then, the expression given can only be rewritten as:

2 (x ^ 2 + x ^ 3)

This is taking common factor 2 to both terms.

Answer:

2 (x ^ 2 + x ^ 3)

7 0
4 years ago
Y=x+3 <br> 2x-y=-1<br> write solution as ordered pair
dsp73

The first equation tells you that y=x+3. If you substitute this expression for y in the second, we have

2x-(x+3)=-1 \iff x-3=-1 \iff x=2

And we can deduce y=x+3=2+3=5

5 0
3 years ago
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