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Lisa [10]
3 years ago
9

A clock is reading 10:27:54.0 (hr:min:sec) when it is discovered to be 4 seconds fast. Explain why it is undesirable to set it b

ack to the right time at that point and show (numerically) how it should be adjusted so as to be correct after 8 seconds have elapsed?
Computers and Technology
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

(a)Applications Time Stamp Events

(b)S=0.5(W-T_{skew})+T_{skew}, where T_{skew}≤W≤T_{skew}+8.

Explanation:

Some applications assume that clocks always advance, so they could timestamp events under this assumption.

In our case we have the wrong timed clock, say W and the hardware clock H which is supposed to advance at a perfect rate.

We proceed to construct a software clock such that after 8 seconds we can replace the wrong timed clock with the software clock in good conditions.

Let us denote the software clock with S.

Then, S=c(W-T_{skew})+T_{skew} where:

T_{skew}=The current Time(10:27:54) and;

c is to be found.

We already know that S=T_{skew}+4 when W= T_{skew}+8,

So:

S=c(W-T_{skew})+T_{skew}

T_{skew}+4=c(T_{skew}+8-T_{skew})+T_{skew}

4=8c

c=0.5

We obtain the formula

S=0.5(W-T_{skew})+T_{skew}, where T_{skew}≤W≤T_{skew}+8.

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