Huh we’re, we’re is the computer screen shot
Answer:
The answer is B = 365
Explanation:
The following variable were initialized:
a = 1
b = 10
c = 100
x = 0
Then we store the value of 'c' times 3 in 'x'
x = 3 * c = 3 * 100 = 300
x = 300
Then we add the value of 'b' times 6 to the value already in 'x'
x = x + 'b' times 6
x = x + (b * 6) = 300 + (10 * 6) = 300 + 60 = 360
x = 360
Then we add the value of 'a' times 5 to the value already in 'x'
x = x + 'a' times 5
x = x + (a * 5) = 360 + (1 * 5) = 360 + 5 = 365
x = 365.
Therefore, the value of 'x' displayed is 365.
Answer is
(HMAC)
Hashed Message Authentication Code
This combines authentication via a shared secret
cryptography algorithm key with hashing. It involves the client and server each
with a private key. The client creates a unique hash per request to the server
through hashing the request with private keys.
Answer:
The statement is written in Java.
- System.out.printf("%.5f %.5f %.5f",a,b,c);
Explanation:
Presume that there are three variable a, b and c which have already been declared and initialized with 4.014268319, 14309, 0.00937608 respectively.
To print each of the value with 5 digits to the right of the decimal point, we can use printf() method. We create a format specifier %.5f which is a placeholder of a floating point value. The .5 will specify five digits to the right of the decimal point.
We just create three similar format specifiers ( one for variable a, b, and c, respectively) and include them into printf() method. This will print the output as follows:
4.01427 14309.00000 0.00938
