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kirill115 [55]
3 years ago
5

If an application written for an earlier version of Windows doesn't run correctly the operating system can emulate its own older

version to allow a given program to work with newer hardware or software. The compatibility mode settings in Windows can be changed by: ______________.
a) Right-clicking the program icon and choosing "Restore previous versions" option from the menu
b) Right-clicking the program icon, clicking Properties, and then applying the required settings on the Compatibility tab
c) Right-clicking the program icon and selecting "Run program using recommended compatibility settings" option from the pop-up menu
d) Right-clicking the program icon and selecting "Run as administrator" option from the pop-up menu

Computers and Technology
1 answer:
n200080 [17]3 years ago
7 0

Answer:

The answer is b) Right-clicking the program icon, clicking Properties, and then applying the required settings on the Compatibility tab.

Explanation:

If you have to run an application on a specific operating system, you have to configure the compatibility by accessing in its Properties, then Compatibility tab, and configure the operating system properly.

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Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and
Y_Kistochka [10]

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

4 0
3 years ago
On the CallCenterReport worksheet, add formulas that will summarize the issues for the department entered in cell B3. In cell B6
grin007 [14]

Answer:

In cell B6, formula =INDEX(INDIRECT($B$3),A6)

CallCenter Worksheet Details:

The image of the CallCenter Report worksheet for reference to the question asked is attached below.

Explanation:

Firtsly, an absolute reference in Excel refers to a reference that is "locked" so that rows and columns won't change when copied. To do this,we put a $ dollar sign ( =A$1,) before the row coordinate to lock only the row.

A relative reference in Excel is a cell address without the $ sign in the row and column coordinates example A1.

Having known what absolute and relative reference are, we wlil write the below formula in cell B6 that will later be copied to cell B9:

: =INDEX(INDIRECT($B$3),A6)

5 0
3 years ago
Select the standardized features of Windows that make it easier to manage your tools:
anygoal [31]

Answer: The Standardized feature of Windows that make it easier to manage tools are:

1. Toolbar

2. Menu

3. Taskbar

Explanation: 1. Toolbar helps to easily show the various tools that can be used on Windows.

2. Menu helps to separate the different parts of the Windows for easy access.

3. Taskbar helps to show the various tools for doing a task.

5 0
3 years ago
Given numrows and numcols, print a list of all seats in a theater. rows are numbered, columns lettered, as in 1a or 3e. print a
trapecia [35]

/* package whatever; // don't place package name! */

import java.util.*;

import java.lang.*;

import java.io.*;

class NestedLoops {

public static void main (String [] args) {

int numRows = 4;

int numCols = 5;

int i,j;

char ch = 'A';

// Note: You'll need to declare more variables

/* Your solution goes here */

for ( i = 0; i < numRows; i++) { // Outer loop runs for numRows times

for ( j = 0; j < numCols; j++) { // Inner loop runs for numCols times

System.out.print(i+1);

System.out.print((char)(ch+j));

System.out.print(" ");

}

}

System.out.println("");

return;

}

}

8 0
3 years ago
A colleague is complaining about the slowness of a desktop computer, and you explain that the slowness is
mr_godi [17]

Answer:

You are explaining a virtual server

I hope this is correct.

Explanation:

A virtual platform is a software based system that can fully mirror the functionality of the platform, it provides full visibility

A virtual server, on the other hand converts one physical server into multiple virtual machines that can each run their own operating system, it is hosted by a offsite dsta center

6 0
2 years ago
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