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Shtirlitz [24]
3 years ago
6

One angle of a triangle measures 132°. The other two angles are congruent. Enter and solve an equation to find the measure x of

the congruent angles. An equation is ( ) = 180. The congruent angles each measure ( ) °.
Mathematics
1 answer:
aleksandrvk [35]3 years ago
3 0

the equation for the angles will be 180=132+2x where x is one of the smaller angles so this makes it into 48=2x or x=24 meaning that each of the smaller angles are 24

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What is the solution of log, 729= 3?<br> Of<br> 18<br> 81
Reptile [31]
Answer:
Solution
Step-by-step explanation:
Rewrite logx729= 3 is an exponential form using the definition of a logarithm. If x and b are positive real numbers and b≠1, then logb(x)= y is equivalent to b^y = x.
X^3 = 729
Take cube root on both side and we get
x= 3√729
now we firstly simplify the 3√729
Rewrite 729 as 9^3
x = 3√9^3
pull terms out from under the redical, assuming positive real numbers
x=9
verify each of the solution by substituting them into logx729=3 and solving.
x= 9
5 0
3 years ago
A line has a rise of 6 and a slope of 1/20. What is the run?<br> 30<br> 90<br> 120
MrRissso [65]

Answer:

120

Step-by-step explanation:

6/120 = 1/6

6 divided by what would simplify to 1/6?

120

6 0
3 years ago
Use the augmented matrix method to solve the following system of equations. Your answers may be given as decimals or fractions.
Alexandra [31]

Answer:

x\ =\ \dfrac{21}{5}

y\ =\ \dfrac{3}{5}

z = 2

Step-by-step explanation:

Given equations are

x - 2y - z = 2

x + 3y - 2z = 4

-x + 2y + 3z = 2

from the given equations the augmented matrix can be written as

\left[\begin{array}{ccc}1&-2&-1:2\\1&3&-2:4\\-1&2&3:2\end{array}\right]

R_2=>R_2-R_1\ and\ R_3=>R_3+R_1

=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&5&-1:2\\0&0&2:4\end{array}\right]

R_2=>\dfrac{R_2}{5}

=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\0&0&2:4\end{array}\right]

R_1=>R_1+2.R_2

=\ \left[\begin{array}{ccc}1&0&-1-\dfrac{2}{5}:2+\dfrac{4}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]

=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]

R_3=>\dfrac{R_3}{2}

=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&1:2\end{array}\right]

R_1=>R_1+\dfrac{7}{5}R_3\ and\ R_2+\dfrac{1}{5}R_3

=\ \left[\begin{array}{ccc}1&0&0:\dfrac{14}{5}+\dfrac{7}{5}\\\\0&1&0:\dfrac{2}{5}+\dfrac{1}{5}\\\\0&0&1:2\end{array}\right]

So, from the above augmented matrix, we can write

x\ =\ \dfrac{21}{5}

y\ =\ \dfrac{3}{5}

z = 2

7 0
3 years ago
Question is attached could you please help me and explain how you got your answer?
vampirchik [111]
Okay so combine like terms
10x-4x= 6x
2-8= -6

6x=-6
x= -1

Now to check:
10(-1)-2=4(-1)-8
-10-2=-4-8
-12=-12
3 0
3 years ago
Read 2 more answers
Will mark brainliest!!
wlad13 [49]
<span>Solve the system

9x = 27-9y
20x=71-9y

Let's use the "elimination through addition/subtraction method.
Multiply the first equation by -1 so as to obtain +9y:

-9x = -27 + 9y
</span><span>20x=  71-   9y
--------------------

Add these 2 equations together:

</span>-9x = -27 + 9y
20x=  71-   9y
--------------------
<span> 11x = 44

Solve this for x:  x = 44/11 = 4.

Now find y by subst. 4 for x in either of the original equations.

Using the second equation:    </span><span> 

</span>20x=71-9y
20(4) = 71 - 9y
80-71 = -9y
9 = -9y.  Then y = -1.

The solution set is (4,-1).
7 0
3 years ago
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