Answer:
x=40
Step-by-step explanation:
x= 360-(273+47)
Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.
Answer:
θ = -33.69°
Step-by-step explanation:
For Φ>0 and Φ<0 (in general Φ≠nπ where n is an integer), sin(Φ) ≠ 0
Dividing both equations:
Therefore:
arctan(θ) = -2/3
θ = -33.69°
The answer does not depend on the sign of Φ, in fact we just need that the sine does not become zero, which occurs when Φ is equal to an integer times π (radians) or 180 (degrees)
Have a nice day!
Answer:
<h3>9.9s</h3>
Step-by-step explanation:
First note that the river is on the ground level. The height of the river at the ground level is 0
Given the the height h above the river in feet of water going over the edge of the waterfall is modeled by h(t)=-16t^2+1552
When h = 0
0 = -16t^2+1552
16t^2 = 1552
t² = 1552/16
t² = 97
t = √97
<em>t = 9.9secs</em>
<em>Hence the time it takes is 9.9secs to the nearest tenth</em>
Answer:
≈ 6.16
Step-by-step explanation:
Calculate the distance (d) using the distance formula
d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = C(5, - 5) and (x₂, y₂ ) = D(7, 3)
d = √ (7 - 5)² + (3 + 5)²
= √ 2² + 8² = √ 4 + 64 = √68 ≈ 6.16 ( to 2 dec. places )
