The events A and B are independent if the probability that event A occurs does not affect the probability that event B occurs.
A and B are independent if the equation P(A∩B) = P(A) P(B) holds true.
P(A∩B) is the probability that both event A and B occur.
Conditional probability is the probability of an event given that some other event first occurs.
P(B|A)=P(A∩B)/P(A)
In the case where events<span> A and B are </span>independent<span> the </span>conditional probability<span> of </span>event<span> B given </span>event<span> A is simply the </span>probability<span> of </span>event<span> B, that is P(B).</span>
Statement 1:A and B are independent events because P(A∣B) = P(A) = 0.12. This is true.
Statement 2:<span>A and B are independent events because P(A∣B) = P(A) = 0.25.
This is true.
Statement 3:</span><span>A and B are not independent events because P(A∣B) = 0.12 and P(A) = 0.25.
This is true.
Statement 4:</span><span>A and B are not independent events because P(A∣B) = 0.375 and P(A) = 0.25
This is true.</span>
Answer:
11 3/13% per annum
Step-by-step explanation:
to find rate= 100×simple interest ÷ (principal ×time)
simple interest=total amount - principal
=1,500,000-1,300,000
=200,000
=200,000 ×100÷ 1,300,000×4
=3 11/13% per annum
Answer:
<h2>C. g(x) = x - 6</h2>
Step-by-step explanation:
For a parent function y = f(x) and n > 0:
f(x) + n : move the graph n units up
f(x) - n : move the graph n units down
f(x + n) : move the graph n units to the left
f(x - n) : move the graph n units to the right
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We have
f(x) = x
Transformation: 6 units down
f(x) - 6 = x - 6
The answer to that question is 62x ()//‘’::;;
c^2 = a^2 + b^2 - 2(ab)(cos C)
c^2 + 2(ab)(cos C) = a^2 + b^2
2(ab)(cos C) = a^2 + b^2 - c^2
cos C = (a^2 + b^2 - c^2) / 2ab - Answer choice E
Hope this helps! :)