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maw [93]
3 years ago
13

A taxi ride cost $1.25 plus $0.75 per mile. If the total cost of the trip is $12.50, how many miles did the passenger travel?

Mathematics
1 answer:
Talja [164]3 years ago
6 0
Roughly 15 miles
d.15 
$12.50 -1.25=11.25
11.25 divided by o.75= 15.0714286 so roughly 15 or 16ish
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MrRissso [65]
The Karger's algorithm relates to graph theory where G=(V,E)  is an undirected graph with |E| edges and |V| vertices.  The objective is to find the minimum number of cuts in edges in order to separate G into two disjoint graphs.  The algorithm is randomized and will, in some cases, give the minimum number of cuts.  The more number of trials, the higher probability that the minimum number of cuts will be obtained.

The Karger's algorithm will succeed in finding the minimum cut if every edge contraction does not involve any of the edge set C of the minimum cut.

The probability of success, i.e. obtaining the minimum cut, can be shown to be ≥ 2/(n(n-1))=1/C(n,2),  which roughly equals 2/n^2 given in the question.Given: EACH randomized trial using the Karger's algorithm has a success rate of P(success,1) ≥ 2/n^2.

This means that the probability of failure is P(F,1) ≤ (1-2/n^2) for each single trial.

We need to estimate the number of trials, t, such that the probability that all t trials fail is less than 1/n.

Using the multiplication rule in probability theory, this can be expressed as
P(F,t)= (1-2/n^2)^t < 1/n 

We will use a tool derived from calculus that 
Lim (1-1/x)^x as x->infinity = 1/e, and
(1-1/x)^x < 1/e   for x finite.  

Setting t=(1/2)n^2 trials, we have
P(F,n^2) = (1-2/n^2)^((1/2)n^2) < 1/e

Finally, if we set t=(1/2)n^2*log(n), [log(n) is log_e(n)]

P(F,(1/2)n^2*log(n))
= (P(F,(1/2)n^2))^log(n) 
< (1/e)^log(n)
= 1/(e^log(n))
= 1/n

Therefore, the minimum number of trials, t, such that P(F,t)< 1/n is t=(1/2)(n^2)*log(n)    [note: log(n) is natural log]
4 0
3 years ago
If 2x = 5, 3y = 4, and 4z = 3, what is the value of 24xyz ?
NISA [10]
2x=5 so 5÷2 = x (2.5)
3y = 4 so 4÷3 = y (1.3 recurring)
4z = 3 so 3÷4 = z (0.75)

implement: 24x2.5x1.3•x0.75

hope i answered right
3 0
3 years ago
Can someone help me please ? Thanks!
notka56 [123]
Use pythagorean theorem for all of them
a. 3, 4, 5
3^2+4^2?5^2
9+16?25
25=25
right 

b. 5, 6, 7
5^2+6^2=7^2
25+36=49
61>49
acute

c. 64+81=144
145>144
acute

hope this helps!
6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=55%20%5Cfrac%7B6%7D%7B9%3F%7D%20%20%5Ctimes%2066%20%5Cfrac%7B5%7D%7B6%7D%20" id="TexFormula1"
JulsSmile [24]

Answer:

Step-by-step explanation:

If you can present a problem in Latex, you can do anything. I don't know what the question mark is for. I'm just ignoring it.

55 2/3 * 66 5/6

One of the ways to get the answer is to use decimals

55.666666667 * 66.833333333 = 3720.38889

Another way to do this problem is to break up one of the numbers

55 2/3 (66 + 5/6)   You can do this if you know how to use the distributive property.

55 2/3 * 66 + 55 2/3 * 5/6

( (165 + 2) / 3) * 66 + (165 + 2)/3 * 5/6

167/3 * 66 + 167 / 3 * 5/6

167 * 22 + (167 * 5 / (3 * 6)

3674 + 835 / 18

3674 + 46 7/18

3720 7/18

If none of these seem right and you have choices, please list them.  

6 0
3 years ago
A rectangular garden is 15 ft longer than it is wide. Its area is 6750 ft 2 . What are its dimensions
xxMikexx [17]

Answer:

450 x 15 = 6750 ft 2

Step-by-step explanation:

6 0
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