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3 years ago

Please solve this ASAP for 30 points

Mathematics

1 answer:

e-lub [12.9K]3 years ago

3 0

Answer:

welpp

Step-by-step explanation:

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Questions (no partial grades if you don't show your work) 1. In a group of 6 boys and 4 girls, four children are to be selected.

mariarad [96]

Answer:

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)

Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = $^{6}C_{1}\times^{4}C_{3}=6\times4$ =24

2 Boy and 2 girls= $^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90$

3 Boys and 1 girl = $^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80$

4 Boys = $^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15$

Now total number of ways = 24 + 90 + 80 + 15 = 209

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3 years ago

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noname [10]

(A) is the answer yes is A

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2 years ago

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jolli1 [7]

Answer:

Step-by-step explanation:

yeah

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tankabanditka [31]

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Step-by-step explanation:

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Which point doesn’t have multiply ranges for a x value?

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