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3 years ago

I really need some one to solve this please!!!

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

7 0

Answer:

x=10

Step-by-step explanation:

Hey There!

Our goal to solve this problem is to get the variable on one side and the constant on the other using inverse operations

$\frac{2x-5}{3} =5$

step 1 multiply each side by 3

3x5=15

3x/3 cancels out

now we have 2x-5=15

step 2 add 5 to each side

-5+5 cancels out

15+5=20

now we have

20=2x

step 3 divide each side by 2

20/2=10

we're left with x=10

BartSMP [9]3 years ago

4 0

Answer:x=10/3

Step-by-step explanation:

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emmainna [20.7K]

Answer:

4:7 and 4:49

Step-by-step explanation:

P=s+s+s

A=S×S

3 0

3 years ago

26287091 rounded to 5 decimal places

timama [110]

<span>rounded to 5 decimal places: 26287091.00000</span>

7 0

3 years ago

(3×²+5y²)³=<br><br> (2y³-×5)²=

irakobra [83]

First one:
(3x^2+5y^2)^3
Step 1: Use the binomial theorem to expand
(3x^2)+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)2+(5y^2)^3
Step 2: Simplify each term
27(x^2)^3+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
Step 3: Multiply the exponents
27x^6+27x^4(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
27x^5+135x^4y^2+3(3x^2)(5y^2)^2+(5y^2)^3
Keep going to get the final answer:
27x^6+135x^4y^2+225x^2y^4+125y^6

2nd question: (2y^3-5x)^2
Do the same thing...step by step
Answer: 4y^6-20xy^3+25x^2

7 0

3 years ago

Coal is carried from a mine in West Virginia to a power plant in New York in hopper cars on a long train. The automatic hopper c

aalyn [17]

Answer:

a) This means that there is a 33% probability that one car chosen at random will have less than 49.5 tons of coal.

b) There is a 0.04% .probability that 35 cars chosen at random will have a mean load weight of less than 49.5 tons of coal

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The actual weights of coal loaded into each car are normally distributed, with mean = 50 tons and standard deviation = 0.9 ton. This means that $\mu = 50, \sigma = 0.9$

(a) What is the probability that one car chosen at random will have less than 49.5 tons of coal? (Round your answer to four decimal places.)

This is the pvalue of Z when $X = 49.5$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{49.5 - 50}{0.9}$

$Z = -0.44$

$Z = -0.44$ has a pvalue of 0.33.

This means that there is a 33% probability that one car chosen at random will have less than 49.5 tons of coal.

(b) What is the probability that 35 cars chosen at random will have a mean load weight of less than 49.5 tons of coal? (Round your answer to four decimal places.)

Now we have to use the standard deviation of the sample, since we are working with the sample mean. That is

$s = \frac{\sigma}{\sqrt{n}} = \frac{0.9}{\sqrt{35}} = 0.15$