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GrogVix [38]
3 years ago
10

The amount of time a certain brand of light bulb lasts is normally distributed with a

Mathematics
1 answer:
scoundrel [369]3 years ago
5 0

Answer:

92.65 % light bulbs last less than 2080 hours

Step-by-step explanation:

We are given that The amount of time a certain brand of light bulb lasts is normally distributed

Mean =\mu = 2000

Standard deviation =\sigma = 55

We are supposed to find  What percentage light bulbs last less than 2080 hours, to the nearest tenth

Z = \frac{x-\mu}{\sigma}\\\\Z=\frac{2080-2000}{55}

Z=1.45

Refer the z table for p value

p value = 0.9265

Hence 92.65 % light bulbs last less than 2080 hours

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VladimirAG [237]

The percentage that the number of airlines with an average airplane age of 14 is less than the number of airlines with an average airplane age of 11 is:

B. 20%.

<h3>What is a percentage?</h3>

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

P = \frac{a}{b} \times 100\%

The percentage of airlines with an average age of 14 years is:

P = \frac{2}{15} \times 100\% = 13.33\%

The percentage of airlines with an average age of 11 years is:

P = \frac{5}{15} \times 100\% = 33.33\%

The difference is:

33.33% - 13.33% = 20%.

Hence option B is correct.

More can be learned about percentages at brainly.com/question/10491646

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2 years ago
Find the area of the figure
Amanda [17]

Answer:

A ≈ 26.42

Step-by-step explanation:

<em><u>The shape presented is a circle, and the formula for this is:</u></em>

A = πr^2

<em><u>The "</u></em>r<em><u>," is the radius (2.9), so plug this into the formula:</u></em>

A = π(2.9)^2

A = π8.41

A ≈ 26.42

4 0
4 years ago
What is the surface area?​
Alchen [17]

Answer:

SA: 1575.2

Step-by-step explanation:

(22)(22) + (26)(22) = (23.6)(22)

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I hope I helped you ;)

6 0
3 years ago
Anyone help me. ....​
weeeeeb [17]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

All the exponents inside the parenthesis are multiplied by the exponent outside the parenthesis.

Then

\frac{m^{-7}n^{14}  }{m^{-25}n^{40}  } ÷ \frac{m^{-21}n^{42}  }{m^{-25}n^{40}  }

[ Using the rule \frac{a^{m} }{a^{n} } = a^{(m-n)} ]

= m^{(-7-14)} n^{(14-(-28)} ÷ m^{(-15-10)} n^{(25-(-15)}

= m^{-21} n^{14+28} ÷ m^{-25} n^{25+15}

= \frac{m^{-21}n^{42}  }{m^{-25}n^{40}  }

= m^{(-21-(-25))} n^{(42-40)}

= m^{(-21+25)} n²

= m^{4} n² = m^{x} n^{y} , so x = 4 and y = 2

Then

m^{x-2y} = m^{4-2(2)} = m^{4-4} = m^{0} = 1 ← as required

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3 years ago
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murzikaleks [220]
I hope this helps you

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3 years ago
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