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MAXImum [283]
3 years ago
12

You have a 4 in. X 6in. family picture that you want to resize. You can choose from a 16 in. X 20 in. or an 18 in. X 24 in. Whic

h size will keep more of the original picture?

Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

16 in × 20 in

Step-by-step explanation:

  1. Finding the % of the picture that can fit in 16×20 frame

Area of picture= length by width

                         =4*6=24 in²

Area of frame=Length by width

                      =16*20=320 in²

% of the picture in the frame will be

                        (24/320) * 100% =7.5%

     2. Finding the % of the picture that can fit in 18 × 24 frame

Area of picture=24 in²

Area of frame =Length by width

                       =18*24=432 in²

% of the picture in the frame will be;

                        (24/432)*100%=5.6%

The frame 16 by 20 in will keep 7.5% of the original picture

The frame 18 by 24 in will keep 5.6% of the original picture

Hence you should use the frame  of 16 by 20 in because it will keep more of the original picture.

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=16×7×7×20

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7.

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What is the GCF of 60 and 24
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A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

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What number is 66% of 29.5
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