180-2(55)-x=0
180-110-x=0
70-x=0
-x=-70
x=70°
<span>x² +y² -4x -6y +8=0
(x² -4x) +(y² -6y) = -8
We are going to complete square for x and y,
it should look like a²+2ab+b² = (a +b)², or </span>a²-2ab+b² = (a -b)²,
<span>
(x²-2*2x+2²) -2² + (y²-2*3y +3²)-3²=- 8
(x-2)²+(y-3)²-4-9=-8
</span>(x-2)²+(y-3)²=-8+13
(x-2)²+(y-3)²=5
<span>
Formula a circle (x-h)²+(y-k)²=R², where vertex has coordinates (h, k)
So , for our circle vertex (2,3) and radius = </span>√5<span>
</span>
The answer is A. 4.51 ft. Hope this helps! :)
Answer:
I will attach the missing drawing with the answer.
9.b)
Plane JKM
Plane JLM
Plane KLM
Step-by-step explanation:
The drawing for this question is missing. I will attach it with the answer.
9.a) Plane JKL is not an appropriate name for the plane because all of three points lie in the same line.
Through a line pass infinite planes. The plane JKL doesn't define a unique plane. That's why plane JKL isn't an appropriate name for the plane.
9.b) We can name the plane using three points that don't lie in the same line.
Three possible names for the plane are :
Plane JKM
Plane JLM
Plane KLM